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Artemon [7]
3 years ago
7

How is matter changed from one state of matter to another? *

Physics
1 answer:
Digiron [165]3 years ago
4 0

Explanation:

Matter is changed from one state to another by addition or removal of heat and suitable pressure conditions.

When a solid is heated, it normally melts and changes to liquids which on heating changes to vapor. The randomness of the particles increases from solid to liquid state and to gaseous states.

Also, a gas can be cooled to liquid and on further cooling transformed into a solid matter.

These phase changes are brought about by energy changes in a system. Some form of matter can also sublime by changing form solid to gas and vice versa.

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Which material is not a fluid? water cork gasoline air
Step2247 [10]

Answer:

Cork

Explanation:

Cork is a solid, other ones are fluid.

3 0
3 years ago
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when you catch a baseball ,what kind of work do you do ,negative or positive ? by catching the ball , what do you change ? what
Alex Ar [27]
You would use negative energy. You change the balls energy by stopping it and oc course it loses energy becasue it has stoped in your hand.
4 0
4 years ago
The density of paper is 1.20 g/cm3. what is the mass of the paper in a notebook that is 76 mm thick, 215.9 mm wide, and 279.4mm
bixtya [17]
<span>Density is a value for mass, such as kg, divided by a value for volume, such as m3. Density is a physical property of a substance that represents the mass of that substance per unit volume. To determine the mass, we calculate the volume of the paper and multiply to the density. We do as follows:

Volume =  76 mm x 215.9 mm x 279.4 mm = 4584506.96 mm^3 or 4584.51 cm^3

Mass = 1.20 g/cm^3 ( 4584.51 cm^3 ) = 5501.41 g</span>
6 0
4 years ago
Radio wave radiation falls in the wavelength region of 10.0 to 1000 meters. What is the energy of radio wave radiation that has
dmitriy555 [2]

Answer:

Explanation:

Given

Wavelength of radiation \lambda =784\ m

We know Energy of wave with wavelength \lambda is given by

E=\frac{hc}{\lambda }

where h=Planck's constant

c=velocity of light

\lambda=wavelength of wave

E=\frac{6.626\times 10^{-34}\times 3\times 10^8}{784}

E=2.53\times 10^{-28}\ J

Hence the energy of the wave with wavelength 784 m is 2.53\times 10^{-28}\ J

7 0
3 years ago
Two antennas located at points A and B are broadcasting radio waves of frequency 96.0 MHz, perfectly in phase with each other. T
earnstyle [38]

Answer:

a)   Δφ = 1.51 rad , b)  x = 21.17 m

Explanation:

This is an interference problem, as they indicate that the distance AP is on the x-axis the antennas must be on the y-axis, the phase difference is

          Δr /λ = Δfi / 2π

          Δfi = Δr /λ 2π

          Δr = r₂-r₁

let's look the distances

         r₁ = 57.0 m

We use Pythagoras' theorem for the other distance

         r₂ = √ (x² + y²)

         r₂ = √(57² + 9.3²)

         r₂ = 57.75 m

The  difference is

         Δr = 57.75 - 57.0

         Δr = 0.75 m

Let's look for the wavelength

        c =  λ f

          λ = c / f

          λ = 3 10⁸ / 96.0 10⁶

          λ = 3.12 m

Let's calculate

         Δφ = 0.75 / 3.12 2π

         Δφ = 1.51 rad

b) for destructive interference the path difference must be λ/2, the equation for destructive interference with φ = π remains

           Δr = (2n + 1) λ / 2

           

For the first interference n = 0

           Δr = λ / 2

           Δr = r₂ - r₁

We substitute the values

        √ (x² + y²) - x = 3.12 / 2

Let's solve for distance x

          √ (x² + y²) = 1.56 + x

          x² + y² = (1.56 + x)²

          x² + y² = 1.56² + 2 1.56 x + x²

          y2 = 20.4336 +3.12 x

          x = (y² -20.4336) /3.12

          x = (9.3² -20.4336) /3.12

          x = 21.17 m

This is the distance for the first minimum

6 0
3 years ago
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