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3 years ago

How is matter changed from one state of matter to another? *

Physics

1 answer:

Digiron [165]3 years ago

4 0

Explanation:

Matter is changed from one state to another by addition or removal of heat and suitable pressure conditions.

When a solid is heated, it normally melts and changes to liquids which on heating changes to vapor. The randomness of the particles increases from solid to liquid state and to gaseous states.

Also, a gas can be cooled to liquid and on further cooling transformed into a solid matter.

These phase changes are brought about by energy changes in a system. Some form of matter can also sublime by changing form solid to gas and vice versa.

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An electron in an electron gun is accelerated from rest by a potential of 25 kV applied over a distance of 1 cm.

podryga [215]

Answer:

$9.38\times 10^7 m/s$

Explanation:

We are given that

Potential ,V=25 kV= $25\times 10^3 V$

Distance,r =1 cm= $\frac{1}{100}=0.01 m$

1 m=100 cm

Mass of electron, m= $9.1\times 10^{-31} kg$

Charge, q= $1.6\times 10^{-19} C$

We have to find the final velocity of the electron.

Speed of electron, $v=\sqrt{\frac{2qV}{m}}$

Using the formula

$v=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 25\times 10^3}{9.1\times 10^{-31}}$

v= $9.38\times 10^7 m/s$

Hence, the final velocity of the electron= $9.38\times 10^7 m/s$

3 0

4 years ago

A plane traveling horizontally at 120 m/s over flat ground at an elevation of 3610 m must drop an emergency packet on a target

antoniya [11.8K]

Answer:

Explanation:

Horizontal displacement

x = 120 t

Vertical position

y = 3610 - 4.9 t²

y = 0 for the ground

0 = 3610 - 4.9 t²

t = 27.14 s

This is the time it will take to reach the ground .

During this period , horizontal displacement

x = 120 x 27.14 m

= 3256.8 m

So packet should be released 3256.8 m before the target.

8 0

3 years ago

Read 2 more answers

Use Kepler's third law to find the planet's average distance (semimajor axis) from its star. (Hint: Because the mass of the star

konstantin123 [22]

Answer:

Explanation: The planet average distance = 42300km

Kepler's 3rd Law also known as the Harmonic Law states that;

for each planet orbitting the sun, its side real period squared divided by the cube of the semi-major axis of the orbit is a constant.

A planet, mass m, orbits the sun, mass M, in a circle of radius r and a period t. The net force on the planet is a centripetal force, and is caused the force of gravity between the sun and the planet.

Please find the attached file for the solution

3 0

3 years ago

A small block of mass M = 0.10 kg is released from rest at point 1 at a height H = 1.8 m above the bottom of a track, as shown i

Ede4ka [16]

Answer:

Explanation:

A) is not correct, because the gravitation potential energy will depend on the height the block is located at. It will be calculated with the formula:

U=mgh.

If we take the ground as a zero height reference, then on point 2 the potential energy will be:

$U_{2} = 0.10kg(9.81 m/s^{2})(0.6m)$

$U_{2}=0.59 J$

While on point 3, the potential energy will be greater.

$U_{3}=0.10kg(9.81 m/s^{2})(1.2m)$

$U_{3}=1.18 J$

B) is not the right answer because the kinetic energy will vary with the height the block is located at in the fact that the energy is conserved (this is if we don't take friction into account or air resistance) so in this case:

$U_{2}+K_{2}= U_{3}+K_{3}$

We already know the potential energy at point 2. We can calculate the kinetic energy at point 3 like this:

$K_{3} =\frac{1}{2}mv_{3}^{2}$

$K_{3} =\frac{1}{2}(0.10kg)(2.5 m/s)^{2}$

$K_{3} =0.31 J$

So the kinetic energy at point 2 is given by the equation:

$K_{2} =U_{3}-U_{2}+K_{3}$

so:

$K_{2} = (1.18J)-(0.59J)+0.31J$

$K_{2} =0.9J$

As you may see the kinetic energy at point 2 is greater than the kinetic energy at point 3.

C) Is not correct because according to the first law of thermodinamics, energy is not lost, only transformed. So, since we are not taking into account friction or any other kind of loss, then we can say that the amount of mechanical energy at point 1 is exactly the same as the mechanical energy at point 3.

D) Because of what we talked about on part C, this will be the true situation, because the mechanical energy of the block will be the same no matter theh point you measure it at.

7 0

3 years ago

Jonah observes the Sun through a special filtered telescope during a total solar eclipse. He sees a red ring and a faint white r

skelet666 [1.2K]

He is seeing the chromosphere and the corona

4 0

3 years ago

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