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tatuchka [14]
4 years ago
7

The assessment technique used by health care providers that utilizes a stethoscope to listen to lung sounds is called A. palpati

on. B. percussion. C. observation. D. auscultation.
Physics
2 answers:
pshichka [43]4 years ago
7 0

Answer: D. auscultation.

Explanation: In auscultation, the healthcare professional can listen to sounds that are produced in the body. For example, he or she may use a stethoscope to listen to the lungs and hear the patient’s breath sounds. Patients without any disease process occurring in the lungs should have clear breath sounds. In a patient who has an infection or has fluid in the lungs, the healthcare professional hears crackles and noises within the lungs. Some sounds, like cracking joints, can be heard without a stethoscope... PF

maw [93]4 years ago
6 0
The answer is D. auscultation
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In a material for which o=5.0 S/m and e, =1 the electric field intensity is E- 250 sin 10" (V/m). Find the conduction and displa
Elodia [21]

Answer:

Explanation:

Given that:

The conductivity of the material \sigma = 5.0 s/m

The  \ relative  \ permittivity \  of \  the \  material {\varepsilon_r} = 1 ; &

The electric field intensity of the material E = 250 sin(10¹⁰ t) V/m

(a) The conduction current density ( J_c) = \sigma E

= 5.0 \times 250 \ sin ( 10^{10} \ t )

\mathbf{ = 1250 \ sin (10 ^{10} t ) \ A/m^2 }

(b)  Displacement  current density (J_d) = \varepsilon _d * \dfrac{\delta E}{\delta t}

Recall that:

\varepsilon _o  = 8.854 \times 10^{-12}

∴

(J_d) =  8.854 \times 10^{-12} \times \dfrac{d}{dt} \times  (250  \ sin \ (10^{10} \ t))

(J_d) = 8.854 \times 10^{-12} \times 250 \times 10^{10} \times \ cos \ (10^{10} \ t)

(J_d) = 22.135 \ cos \  10^{10} \ t \ A/m^2

(c) The frequency at which J_c  \  and  \  J_d will have the same magnitude is:

f = \dfrac{\sigma}{2 \pi \varepsilon_o \varepsilon_r}

By substitution

f = 18 \times 10^9 \times \dfrac{\sigma }{\varepsilon_r}

f = 18\times 10^9 \times \dfrac{5}{1 }

f = 90 GHz

5 0
3 years ago
An object is dropped from 26 feet below the tip of the pinnacle atop a 702 ft tall building. The height h of the object after t
Dimas [21]

Answer:

6.5 seconds.

Explanation:

Given: h=-16t²+679

When the object reaches the ground, h=0.

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collecting like terms,

⇒ 16t²=679

Dividing both side of the equation by the coefficient of t² i.e 16

⇒ 16t²/16 = 679/16

⇒ t² = 42.25

taking the square root of both side of the equation.

⇒ √t² =√42.25

⇒ t = 6.5 seconds.

4 0
4 years ago
Which of the following are true for E = mc2?
lozanna [386]

The question is very poor.

The answer it's fishing for is choice (b), but the only way to know that is
to observe that the others are even worse, and totally from outer space.

This is a Physics question, for heaven's sake.  Real science is built on
measurements, and nothing gets done by operating with quantities like
a "small" change in mass, or a "great deal" of energy.  This question
causes me to shiver with indignation.

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3 years ago
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Now, to find the accurate number of significant figures when adding measurements, the basic rule for addition is to use the least number of decimal places when reporting the result.

Now, since 3.0 has the least number of decimal places, we report the sum with 1 decimal place and have 12.0 miles as the total distance traveled by the person to reach his destination.

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4 years ago
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avanturin [10]

Answer:

That's about 12 kilometers per hour faster than the average female professional tennis player.

Explanation:

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3 years ago
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