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Alecsey [184]
3 years ago
15

Jan needed to empty 18 gallons of water from a tub into jugs that hold 0.5 gallons of water. How many jugs did Jan need?

Mathematics
2 answers:
Viktor [21]3 years ago
8 0
The answer will be 9
julsineya [31]3 years ago
5 0
The answer would be 36 jugs 
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in order for Brady to earn a b in his biology course, his test scores must average at 80%. ON the first 5 tests, he has an avera
ivanzaharov [21]
In order for him to have a 77% on his first 5 tests, that means the total amount of points earned on those 5 tests was 385 points out of 500 points.
(77*5 out of 5*100 points)
So if we want to add a test and have a 80% average this is what we have to do:
(385+x)/6 = 80 (multiply by 6 on both sides)
385 + x = 480 (minus 385 on both sides)
x = 95

7 0
3 years ago
Read 2 more answers
20 POINTS! Please help, best answer will recessive brainliest answer points as well as 5 stars and a thank you. :)
valentina_108 [34]

Answer:

(3) Diagonals are perpendicular

Step-by-step explanation:

5 0
3 years ago
Read the question and answer. Ignore the c please, its incorrect.
Eddi Din [679]

Answer:

The correct choice is E

Step-by-step explanation:

Neither A, B, C, or D are correct, so the right answer must be E. By the way, E isn't shown in the picture.

5 0
3 years ago
Find the distance between the points given. (-10,3) and (-10,12)
aksik [14]

Answer:

The distance is 9.

Step-by-step explanation:

Just look, that  these points have got the same x-coordinate, 

so they lie  on the same line, which is parallel to the OY axis, 

So  your taks is only  find different  in y-coordinate. That is

12-3 = 9 

5 0
3 years ago
Nancy is making a kite based on the pattern below. About how much binding does Nancy need to cover the edges of the kite?
Ainat [17]

Check the picture below.

so the perimeter of the kite is x+x+y+y, namely 2x + 2y.


\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=\stackrel{hypotenuse}{x}\\ a=\stackrel{adjacent}{8}\\ b=\stackrel{opposite}{15}\\ \end{cases} \\\\\\ x=\sqrt{8^2+15^2}\implies x=\sqrt{289}\implies \boxed{x=17} \\\\[-0.35em] ~\dotfill

\bf \begin{cases} c=\stackrel{hypotenuse}{y}\\ a=\stackrel{adjacent}{8}\\ b=\stackrel{opposite}{4}\\ \end{cases}\implies y=\sqrt{8^2+4^2}\implies y=\sqrt{80}\implies \boxed{y\approx 8.94} \\\\[-0.35em] ~\dotfill\\\\ 2x+2y\implies 2(17)+2(8.94)\implies 51.88\implies \stackrel{\textit{rounded up more}}{51.9}

4 0
4 years ago
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