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inysia [295]
3 years ago
7

Which of the following can be used to prove that triangle EFG is also a right triangle?

Mathematics
2 answers:
galben [10]3 years ago
4 0

Answer:

Prove that KL is equal to c by Pythagorean Theorem.


Step-by-step explanation:

In the two triangles triangle KLM is a right triangle with sides a and b as the two legs of the right triangle .We can apply Pythagorean Theorem to find KL.

In triangle KGF two sides are a and b .If we prove KL=EF then Pythagorean Theorem will be true for triangle KGF and hence we can prove triangle KGF to be a right triangle.

The correct option to prove triangle KGF to be a right triangle is to Prove that KL is equal to c by Pythagorean Theorem.


Vika [28.1K]3 years ago
4 0
<span>Which of the following can be used to prove that triangle EFG is also a right triangle?

Prove that the sum of a and c is greater than b.
Prove that the sum of a and b is greater than c.
Prove that the ratio of EF and KL is greater than 1 and hence, the triangles are similar by AA postulate.
Prove that KL is equal to c by Pythagorean Theorem.

The correct answer is:
</span>Prove that KL is equal to c by Pythagorean Theorem.

It can also be "Prove that triangles are congruent by SSS property and hence angle EGF is equal to angle KML"
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Answer:

The answer is D. 110

Step-by-step explanation:

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X + y = 36
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y + 22 + y = 36
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An important factor in selling a residential property is the number of times real estate, agents show a home. A sample of 21 hom
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Using the t-distribution to build the 99% confidence interval, it is found that:

  • The margin of error is of 3.64.
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<h3>What is a t-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm t\frac{s}{\sqrt{n}}

In which:

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  • t is the critical value.
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  • s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a two-tailed 95% confidence interval, with 21 - 1 = 20 df, is t = 2.086.

The other parameters are given as follows:

\overline{x} = 23, s = 8, n = 21

The margin of error is given by:

M = t\frac{s}{\sqrt{n}} = 2.086\frac{8}{\sqrt{21}} = 3.64

Hence the bounds of the interval are:

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\overline{x} + M = 23 + 3.64 = 26.64

The 99% confidence interval for the population mean is (19.36, 26.64).

More can be learned about the t-distribution at brainly.com/question/16162795

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