1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vsevolod [243]
4 years ago
13

Which nanotechnology product would most likely help the

Physics
1 answer:
KonstantinChe [14]4 years ago
5 0

Answer: OLEDs

Explanation:

The nanotechnology uses the surface of the carbon materials to generate the electricity. The evaporation of water on the surface of carbon materials helps in generation of electrical energy due to generation of thermal energy.

OLEDs can be defined as solid-state devices that comprises of organic molecules like carbon that will create electricity by exposing a surface for generation of thermal energy.

You might be interested in
Captain American throws his shield straight down off a roof with a speed of 50 m/s . What is the acceleration of the shield half
Nutka1998 [239]

<em>IF</em> this is happening on <u>Earth</u>, then the acceleration of gravity wherever the captain and the roof are is about 9.8 m/s² downward.

<em>IF</em> his shield is not affected by air resistance, and it's free to behave under the influence of gravity alone, then its acceleration is <em>9.8 m/s² downward</em>, from the moment it leaves his hand until the moment it hits a building, a tree, a car, a bus, an evildoer, or the ground.  

Whatever speed it has when it leaves his hand, in whatever direction, makes no difference.

6 0
3 years ago
What is the magnitude (in N/C) and direction of an electric field that exerts a 3.50 ✕ 10−5 N upward force on a −1.55 µC charge?
IRISSAK [1]

Answer:

The magnitude of electric field is  22.58 N/C

Solution:

Given:

Force exerted in upward direction, \vec{F_{up}} = 3.50\times 10^{- 5} N

Charge, Q = - 1.55\micro C = - 1.55\times 10^{- 6} C

Now, we know by Coulomb's law,

F_{e} = \frac{1}{4\pi\epsilon_{o}\frac{Qq}{R^{2}}

Also,

Electric field, E = \frac{1}{4\pi\epsilon_{o}\frac{q}{R^{2}}

Thus from these two relations, we can deduce:

F = QE

Therefore, in the question:

\vec{E} = \frac{\vec F_{up}}{Q}

\vec{E} = \frac{3.50\times 10^{- 5}}{- 1.55\times 10^{- 6}}

\vec{E} = - 22.58 N/C

Here, the negative side is indicative of the Electric field acting in the opposite direction, i.e., downward direction.

The magnitude of the electric field is:

|\vec{E}| = 22.58\ N/C

6 0
3 years ago
ANSWERRR PLEASEEEE!!!
GuDViN [60]

Answer:

50N to the left

Explanation:

I'll explain if you ask

6 0
3 years ago
Read 2 more answers
(a) According to Hooke's Law, the force required to hold any spring stretched x meters beyond its natural length is f(x)=kx. Sup
KengaRu [80]

Answer:

a) The work required to stretch the spring from 20 centimeters to 25 centimeters is 0.313 joules, b) The area of the region enclosed by one loop of the curve r(\theta) = 2\cdot \sin 5\theta is 4\pi.

Explanation:

a) The work, measured in joules, is a physical variable represented by the following integral:

W = \int\limits^{x_{f}}_{x_{o}} {F(x)} \, dx

Where

x_{o}, x_{f} - Initial and final position, respectively, measured in meters.

F(x) - Force as a function of position, measured in newtons.

Given that F = k\cdot x and the fact that F = 25\,N when x = 0.3\,m - 0.2\,m, the spring constant (k), measured in newtons per meter, is:

k = \frac{F}{x}

k = \frac{25\,N}{0.3\,m-0.2\,m}

k = 250\,\frac{N}{m}

Now, the work function is obtained:

W = \left(250\,\frac{N}{m} \right)\int\limits^{0.05\,m}_{0\,m} {x} \, dx

W = \frac{1}{2}\cdot \left(250\,\frac{N}{m} \right)\cdot [(0.05\,m)^{2}-(0.00\,m)^{2}]

W = 0.313\,J

The work required to stretch the spring from 20 centimeters to 25 centimeters is 0.313 joules.

b) Let be r(\theta) = 2\cdot \sin 5\theta. The area of the region enclosed by one loop of the curve is given by the following integral:

A = \int\limits^{2\pi}_0 {[r(\theta)]^{2}} \, d\theta

A = 4\int\limits^{2\pi}_{0} {\sin^{2}5\theta} \, d\theta

By using trigonometrical identities, the integral is further simplified:

A = 4\int\limits^{2\pi}_{0} {\frac{1-\cos 10\theta}{2} } \, d\theta

A = 2 \int\limits^{2\pi}_{0} {(1-\cos 10\theta)} \, d\theta

A = 2\int\limits^{2\pi}_{0}\, d\theta - 2\int\limits^{2\pi}_{0} {\cos10\theta} \, d\theta

A = 2\cdot (2\pi - 0) - \frac{1}{5}\cdot (\sin 20\pi-\sin 0)

A = 4\pi

The area of the region enclosed by one loop of the curve r(\theta) = 2\cdot \sin 5\theta is 4\pi.

5 0
3 years ago
The equation for the conservation of mechanical energy is:
marusya05 [52]

Answer:

The answer is A because the equation is  KEi+PEi=KEf+PEf

i means initial (before) and f means final (after)

7 0
3 years ago
Other questions:
  • When a sound wave strikes a smooth, hard surface, the wave is
    9·2 answers
  • Two ice skaters, with masses of 69 kg and 57 kg , stand facing each other on a 18-m-wide frozen river. The skaters push off agai
    9·1 answer
  • This i relatively easy but still, i attached a picture
    5·1 answer
  • Nikola Tesla and Thomas Edison were both pioneers when it came providing electricity to the people. Edison had hired the genius
    8·1 answer
  • Which practice fits the definition of conservation?
    10·1 answer
  • A(n) 591 kg elevator starts from rest. It moves upward for 4.79 s with a constant acceleration until it reaches its cruising spe
    12·1 answer
  • As you change the value of the battery voltage, how does this change the current through the circuit and the resistance of the r
    7·1 answer
  • What happens when two oceanic plates collide?
    14·2 answers
  • How many sub levels does the third energy level have?
    5·1 answer
  • a transformer has 1,400 turns in the primary coil and 100 turns in the secondary coil. if the primary coil is connected to a 120
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!