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3 years ago

When the white ball strikes the other colored balls, what can you say about the total momentum of all of the balls combined?

Physics

1 answer:

IgorC [24]3 years ago

6 0

Momentum is never created or destroyed. It is conserved.

The cue stick gave the cue ball all the momentum there is on the table. There's nothing on the table that can pour in any more momentum.

After the strike, with 15 or 16 balls rolling every which way around the table, the total momentum of all of them combined will be the same as the cue ball's momentum right now, before the strike.

You might be interested in

Jupiter is 317 times more massive than the Earth. Its gravitational attraction is _____ Earth's.

NeTakaya

That all depends on your distance from the center of each planet.

On the surface of Jupiter, the acceleration of gravity is 2.53 times
its value on the surface of the Earth.

6 0

3 years ago

Read 2 more answers

A diffraction grating is made up of slits of width = 340 nm with separation = 790 nm. The grating is illuminated by monchromatic

nika2105 [10]

Answer:

angular width is 0.10 degree

Explanation:

Given data

width = 340 nm

separation d = 790 nm

λ = 520 nm

to find out

how many maxima and width of a spectral line

solution

we know for maxima formula is

m λ = dsinθ

and we know here sinθ is between 0 and 1

so we can say

d is greater than m λ

and

m ≤ d / λ

m ≤ 790 / 520

m ≤ 1.52

its mean we have 3 maxima i.e. 0 , 1 and -1

and

for 1st order m = 1

so mλ = dsinθ

λ = dsinθ

θ = sin^-1 ( λ/d) ................................1

and angular width is

θ = λ/ Nd cosθ

θ = dsinθ / Nd cosθ

θ = tanθ /N ...............................2

so here put θ in 2 equation

angular width = tanθ/N

angular width = tan ( sin^-1 ( 520/790) ) / 500

angular width = tan 41.16 / 500

angular width = 1.7484 × $10^{-3}$ × 180/π

angular width = 0.10 degree

3 0

3 years ago

A hollow spherical planet is inhabited by people who live inside it, where the gravitational is zero. When a very massive space

Ulleksa [173]

Answer:

c) nonzero, directed toward the spaceship

Explanation:

As we know that net gravitational force due to spherical shell inside all its points will always be zero

So if planet is a spherical shell then inside the planet net gravitational force is zero on the people living in it

So when massive spaceship land on the surface of planet then the gravitational force of the spaceship is experienced by the people inside the shell

So here the gravitational force on the people is nonzero and it is towards the spaceship which landed on the surface of planet

5 0

3 years ago

A 1 m3tank containing air at 10oC and 350 kPa is connected through a valve to another tank containing 3 kg of air at 35oC and 15

Sveta_85 [38]

Answer:

- the volume of the second tank is 1.77 m³

- the final equilibrium pressure of air is 221.88 kPa ≈ 222 kPa

Explanation:

Given that;

$V_{A}$ = 1 m³

$T_{A}$ = 10°C = 283 K

$P_{A}$ = 350 kPa

$m_{B}$ = 3 kg

$T_{B}$ = 35°C = 308 K

$P_{B}$ = 150 kPa

Now, lets apply the ideal gas equation;

$P_{B}$ $V_{B}$ = $m_{B}$ R $T_{B}$

$V_{B}$ = $m_{B}$ R $T_{B}$ / $P_{B}$

The gas constant of air R = 0.287 kPa⋅m³/kg⋅K

we substitute

$V_{B}$ = ( 3 × 0.287 × 308) / 150

$V_{B}$ = 265.188 / 150

$V_{B}$ = 1.77 m³

Therefore, the volume of the second tank is 1.77 m³

Also, $m_{A}$ = $P_{A}$ $V_{A}$ / R $T_{A}$ = (350 × 1)/(0.287 × 283) = 350 / 81.221

$m_{A}$ = 4.309 kg

Total mass, $m_{f}$ = $m_{A}$ + $m_{B}$ = 4.309 + 3 = 7.309 kg

Total volume $V_{f}$ = $V_{A}$ + $V_{B}$ = 1 + 1.77 = 2.77 m³

Now, from ideal gas equation;

$P_{f}$ = $m_{f}$ R $T_{f}$ / $V_{f}$

given that; final temperature $T_{f}$ = 20°C = 293 K

we substitute

$P_{f}$ = ( 7.309 × 0.287 × 293) / 2.77

$P_{f}$ = 614.6211119 / 2.77

$P_{f}$ = 221.88 kPa ≈ 222 kPa

Therefore, the final equilibrium pressure of air is 221.88 kPa ≈ 222 kPa

6 0

3 years ago

If a quantity of heat equal to the magnitude of the change in mechanical energy of the water goes into the water, what is its in

Flauer [41]

Increase in temperature of water = 0.53 °C
Explanation:
Change in mechanical energy = Potential energy
Potential energy = mgh
Mass, m = Mass of 1 L water = 1 kg
Acceleration due to gravity, g = 9.81 m/s²
Height, h = 225 m
Potential energy = 1 x 9.81 x 225 = 2207.25 J
Because of this 2207.25 J water gets heated.
Heat energy, E = mcΔT
Mass, m = Mass of 1 L water = 1 kg
Specific heat of water, c = 4200 J/kg/C
Energy, E = 2207.25 J
Change in temperature, ΔT = ?
Substituting
2207.25 = 1 x 4200 x ΔT
ΔT = 0.53 °C
Increase in temperature of water = 0.53 °C

3 0

3 years ago