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Cloud [144]
3 years ago
10

A 200-kg object has a 50-Newton rightward net force being applied to it. What is the magnitude of the rightward acceleration on

the object m/s^2?
Physics
1 answer:
katovenus [111]3 years ago
8 0
The formula for acceleration is force divided by mass.

Force = 50 N

Mass = 200 kg

Acceleration = ???

\frac{50}{200} = \frac{1}{4}

\frac{1}{4} = 0.25

~~

Acceleration = 0.25 m/s²

~~

Next time use, f = ma in a triangle,

F

M A

~~

I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey
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Mama L [17]

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Read 2 more answers
What is the net force (including direction and magnitude) acting on the object on the above left?
Ber [7]

Answer:

Explanation:

the net force on the right left is 25 N and is directed upward

the net force on the left one is zero because 200N force act upward and 200N force act downward so both cancel each other and net force is zero

i hope this will help you

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