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e-lub [12.9K]
2 years ago
8

If x - y =5, x + y =1, then x^2 - y^2= ??+explanation please and thanks​

Mathematics
1 answer:
Sveta_85 [38]2 years ago
8 0
<h3>Answer:  5</h3>

=================================

Explanation:

Apply the difference of squares rule

x^2 - y^2 = (x-y)(x+y)

x^2 - y^2 = (5)(1)

x^2 - y^2 = 5

----------

Alternatively, you can solve the system

\begin{cases}x-y=5\\x+y = 1\end{cases}

for x and y to get (x,y) = (3,-2).

Then compute x^2-y^2 = 3^2-(-2)^2 = 9-4 = 5

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f(x) is an even function, so f(-x) = f(x). Then the inverse relation is double-valued: for any given y, there can be either of two x-values that will give that result.

___

A function is single-valued. That means any given domain value maps to exactly one range value. The test of this is the "vertical line test." If a vertical line intersects the graph in more than one point, then that x-value maps to more than one y-value.

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Since the inverse relation for the given f(x) maps every x to two y-values, it is not a function. You can also tell this by the fact that f(x) is an even function, so does not pass the horizontal line test. When f(x) doesn't pass the horizontal line test, f^-1(x) cannot pass the vertical line test.

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The attached graph shows the inverse relation (called f₁(x)). It also shows a vertical line intersecting that graph in more than one place.

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