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Nana76 [90]
2 years ago
14

In Triangle ABC, AC is extended through C to D. If

Mathematics
1 answer:
DENIUS [597]2 years ago
8 0

Answer:

X  = 5 unit

Step-by-step explanation:

Given as , ABC is a Triangle ,

AC extended to through C to D

∠BAC = 6x + 10

∠ABC = 6x - 10

∠BCD = ∠ 8x + 20

When c extended to D then , ∠BCD is an external angle

∵ <u>External angle = Sum of opposite internal angles</u>

Or ,∠BCD = ∠BAC + ∠ABC

Or, ∠ 8x + 20 = 6x + 10 + 6x - 10

Or, ∠ 8x + 20 = 12x

Or, 12x - 8x = 20

∴ 4x = 20

So, x = \frac{20}{4} = 5

Hence the value of X = 5  unit  Answer

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For the inverse variation equation p = StartFraction 8 Over V EndFraction, what is the value of V when p = one-half?
likoan [24]

Answer:

V=16

Step-by-step explanation:

We are given that an inverse variation

p=\frac{8}{V}

We have to find the value of V when p=1/2

To find the value of V we will substitute the value of p

Substitute the value of p

Then, we get

\frac{1}{2}=\frac{8}{V}

\frac{V}{2}=8

Using multiplication property of equality

V=8\times 2

Using multiplication property of equality

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Hence, the value of V=16

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Step-by-step explanation:

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Step-by-step explanation:

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A national grocery store chain wants to test the difference in the average weight of turkeys sold in Detroit and the average wei
Arte-miy333 [17]

Answer:

<em>Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom</em>

<em>The null hypothesis is accepted . </em>

<em>Assume the population variances are approximately the same</em>

<u><em>Step-by-step explanation:</em></u>

<u>Explanation</u>:-

Given data a random sample of 20 turkeys sold at the chain's stores in Detroit yielded a sample mean of 17.53 pounds, with a sample standard deviation of 3.2 pounds

<em>The first sample size  'n₁'= 20</em>

<em>mean of the first sample 'x₁⁻'= 17.53 pounds</em>

<em>standard deviation of first sample  S₁ = 3.2 pounds</em>

Given data a random sample of 24 turkeys sold at the chain's stores in Charlotte yielded a sample mean of 14.89 pounds, with a sample standard deviation of 2.7 pounds

<em>The second sample size  n₂ = 24</em>

<em>mean of the second sample  "x₂⁻"= 14.89 pounds</em>

<em>standard deviation of second sample  S₂ =  2.7 poun</em>ds

<u><em>Null hypothesis</em></u><u>:-</u><u><em>H₀</em></u><em>: The Population Variance are approximately same</em>

<u><em>Alternatively hypothesis</em></u><em>: H₁:The Population Variance are approximately same</em>

<em>Level of significance ∝ =0.05</em>

<em>Degrees of freedom ν = n₁ +n₂ -2 =20+24-2 = 42</em>

<em>Test statistic :-</em>

<em>    </em>t = \frac{x^{-} _{1} -  x_{2} }{\sqrt{S^2(\frac{1}{n_{1} } }+\frac{1}{n_{2} }  }

<em>    where         </em>S^{2}   = \frac{n_{1} S_{1} ^{2}+n_{2}S_{2} ^{2}   }{n_{1} +n_{2} -2}

                      S^{2} = \frac{20X(3.2)^2+24X(2.7)^2}{20+24-2}

<em>              substitute values and we get  S² =  40.988</em>

<em>     </em>t= \frac{17.53-14.89 }{\sqrt{40.988(\frac{1}{20} }+\frac{1}{24}  )}<em></em>

<em>  </em>   t =  1.3622

  Calculated value t = 1.3622

Tabulated value 't' =  2.081

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

<u><em>Conclusion</em></u>:-

<em>The null hypothesis is accepted </em>

<em>Assume the population variances are approximately the same.</em>

<em>      </em>

<em>                        </em>

<em>                    </em>

6 0
2 years ago
Please help i need this answer quick for a test
Oksi-84 [34.3K]

Answer: the depth of the trench is 3685 ft

Step-by-step explanation:

The hole is approximately 347 yards wide. This means that the diameter of the hole is 347 yards.

The formula for determining the volume of a cylinder is expressed as

Volume = πr²h

Where

r represents the radius of the cylinder or hole.

h represents the height or depth of the cylinder or hole.

π is a constant whose value is 3.14

From the information given,

Volume = 348289500 ft³

Radius = diameter/2 = 347/2 = 173.5 ft

Therefore,

348289500 = 3.14 × 173.5² × h

348289500 = 94521.065h

h = 348289500/94521.065

h = 3685 feet

4 0
3 years ago
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