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3 years ago

I need some one to help me with this

Mathematics

2 answers:

Ahat [919]3 years ago

6 0

$y = 6x - 2$
You can see that each time x increases by 1, y increases by 5. This means that the coefficient of x is 5 (if you graphed it, the slope would be 5). To find what value to add at the end, you can look at what y is when x equals 0. In this case, that is -2 (on a graph, -2 would be the y-intercept).

lys-0071 [83]3 years ago

4 0

Slope = -2-4/ 0-1

-6/-1. Or 6

Y = 6x -2

The -2 comes from where the chart shows (0,-2).

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Answer:

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4 years ago

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riadik2000 [5.3K]

Answer:

The answer is 75 degrees.

Step-by-step explanation:

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3 years ago

Read 2 more answers

Help me class8 (surds)

Mashcka [7]

Answer:

$\cfrac{991\sqrt{2} }{80}$

Step-by-step explanation:

For a start simplify each of the roots:

$\sqrt{72} =\sqrt{36*2} =6\sqrt{2}$
$\sqrt{50} =\sqrt{25*2} =5\sqrt{2}$
$\sqrt{128} =\sqrt{64*2} =8\sqrt{2}$
$\sqrt{98} =\sqrt{49*2} =7\sqrt{2}$

Now simplify the expression in steps:

$\sqrt{72}-\cfrac{48}{\sqrt{50} } -\cfrac{45}{\sqrt{128} } +2\sqrt{98} =$

$6\sqrt{2}-\cfrac{48}{5\sqrt{2} } -\cfrac{45}{8\sqrt{2} } +2*7\sqrt{2} =$

$6\sqrt{2}-\cfrac{48*8+45*5}{5*8\sqrt{2} } +14\sqrt{2} =$

$20\sqrt{2}-\cfrac{609}{40\sqrt{2} } =$

$20\sqrt{2}-\cfrac{609*\sqrt{2} }{40\sqrt{2} *\sqrt{2} } =$

$20\sqrt{2}-\cfrac{609\sqrt{2} }{40*2 } =$

$20\sqrt{2}-\cfrac{609\sqrt{2} }{80 } =$

$\sqrt{2} (20-7\cfrac{49}{80} )=$

$\sqrt{2} *12\cfrac{31}{80} =$

$\cfrac{991\sqrt{2} }{80}$

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2 years ago

Find an equation in standard form for the hyperbola with vertices at (0, ±6) and foci at (0, ±9).

Dvinal [7]

<span>For given hyperbola:
center: (0,0)
a=7 (distance from center to vertices)
a^2=49
c=9 (distance from center to vertices)
c^2=81
c^2=a^2+b^2
b^2=c^2-a^2=81-49=32
Equation of given hyperbola:

..
2: vertices (0,+/-3) foci (0,+/-6)
hyperbola has a vertical transverse axis
Its standard form of equation: , (h,k)=(x,y) coordinates of center
For given hyperbola:
center: (0,0)
a=3 (distance from center to vertices)
a^2=9
c=6 (distance from center to vertices)
c^2=36 a^2+b^2
b^2=c^2-a^2=36-9=25
Equation of given hyperbola:
</span>

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3 years ago

As you were organizing your closet you counted 20 shirts and 12 pairs of pants what was the pants to shirt ratio?

NISA [10]

Answer: 5 : 3

Step-by-step explanation:

The ratio of shirts to pants can be shown by putting the number if shirts and pants in the following manner:

Number of shirts : Number of pants

20 : 12

Then you have to take this to the lowest term. 4 is a factor of both numbers so when divided by 4 we get:

= 5 : 3

This is the ratio.

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3 years ago