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KonstantinChe [14]
3 years ago
6

Explain how you can find the amount of money Juan save if he earned $12 walking dogs

Mathematics
1 answer:
Lisa [10]3 years ago
6 0
You can find how many he gets for each dog.

For example, let's pretend Juan gets $3 for each dog to walk, then he would've walked 4 dogs. But in this real problem we don't know how much he gets for each dog.

So, you can find the amount of money Juan saved by knowing how much is for each dog walked.
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Please help ill give branlist and extra points if yall help me with this
neonofarm [45]
Number 1 is B Number 2 is C
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21<br> 18<br> 15<br> 12<br> 9<br> 6<br> 3<br> 1 2 3 4 5 6 7
PtichkaEL [24]
Sorry what what is the question?
8 0
3 years ago
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Solve this equation<br>5(-7x-3)- 8x=-230​
Brut [27]

Simplifying

5(7x + -3) = 230

Reorder the terms:

5(-3 + 7x) = 230

(-3 * 5 + 7x * 5) = 230

(-15 + 35x) = 230

Solving

-15 + 35x = 230

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '15' to each side of the equation.

-15 + 15 + 35x = 230 + 15

Combine like terms: -15 + 15 = 0

0 + 35x = 230 + 15

35x = 230 + 15

Combine like terms: 230 + 15 = 245

35x = 245

Divide each side by '35'.

x = 7

Simplifying

x = 7

5 0
4 years ago
18x2 + 50 = 0<br> What are the solutions and how do you get them ?
Artist 52 [7]

Answer:86

Step-by-step explanation:

You would do multiplication first so 18x2 = 36 then you would add 36+50 which equals 86

7 0
3 years ago
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Given that f(x) = x + 3<br> a) Find f(2)
Nataly_w [17]

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

In the above question, it is given that :

\qquad \sf  \boxed{ \sf f(x) =  \frac{x + 3}{2} }

A.) Find f(2) :

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{2 + 3}{2}

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{5}{2}

or

\qquad \sf  \dashrightarrow \: f(2) = 0.5

B.) Find { \sf {f}^{-1}(x) } :

\qquad \sf  \dashrightarrow \: let \: y = f (x)

so, we can write it as :

\qquad \sf  \dashrightarrow \: y =  \dfrac{x + 3}{2}

\qquad \sf  \dashrightarrow \: 2y = x + 3

\qquad \sf  \dashrightarrow \: x = 2y - 3

Now, put x = { \sf {f}^{-1}(x) }, and y = x and we will get our required inverse function ~

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3

C.) Find { \sf {f}^{-1}(12) } :

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 2(12)- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 36- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 33

7 0
1 year ago
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