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fiasKO [112]
3 years ago
6

What is the factored for of the polynomial x2 - 16x + 48

Mathematics
2 answers:
mel-nik [20]3 years ago
5 0
What two factors of 48 add up to -16? -4 and -12

So the factored form would be (x-4)(x-12)
galina1969 [7]3 years ago
3 0

Answer:

(x-12)(x-4)

Step-by-step explanation:

x^2 - 16x + 48

In the given expression , the product is 48 and sum is -16

-4 times -12 gives us 48

-4 plus -12 gives us -16. So two factors are -4 and -12

Beak the middle term using factors

x^2 -4x-12x+48

Group first two terms and last two terms

(x^2 -4x)+(-12x+48)

FActor out GCF from each group

x(x -4)-12(x-4)

FActor out x-4 that is in common

(x-12)(x-4)

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Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), a
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Answer:

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Step-by-step explanation:

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EF=\sqrt{(3-1)^2+(5-5)^2}=2\,\,units\\FG=\sqrt{(6-3)^2+(1-5)^2}=\sqrt{9+16}=5\,\,units\\GH=\sqrt{(x-6)^2+(y-1)^2}\\EH=\sqrt{(x-1)^2+(y-5)^2}

Perimeter of a figure is the length of its outline.

EF+FG+GH+EH=16\\2+5+\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16-2-5\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9

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\sqrt{(1-6)^2+(1-1)^2}+\sqrt{(1-1)^2+(1-5)^2}=9\\\sqrt{25}+\sqrt{16}=9\\5+4=9\\9=9

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