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klasskru [66]
3 years ago
12

Etxuck327 Inc. sells a particular textbook for $39. Variable expenses are $28 per book. At the current volume of 49,000 books so

ld per year the company is just breaking even. Given these data, the annual fixed expenses associated with the textbook total:
Business
1 answer:
Westkost [7]3 years ago
5 0

Answer:

539,000.00  

Explanation:

As per the contribution margin analysis concept, the break-even point is obtained by dividing fixed cost by contribution margin per unit.

For Etuck327,

The selling price is $39

Variable expense is $28

Break-even in units is 49,000 books.

Contribution margin per unit = selling price - variable costs

=$39- $28

=$11

if Break-even = fixed cost/ contribution margin per unit, then

49,000= fixed cost / 11

fixed costs = 11 x 49000

Fixed costs = 539,000.00    

                   

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Park is always willing to give up 1 orange for 3 tangerines. (1) What is the size of MRSTO (marginal rate of substituting tanger
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Are female expatriates different?.​
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Read 2 more answers
Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the
Sonbull [250]

Answer:

Mean = 47

Median = 47.38

Standard Deviation = 12.73

Explanation:

Note: You wrote " 40 manufacturing companies, but the total number of companies you actually listed is 75, definitely you meant 75.

Let y represent the range of advertising expenditure, f represent the number of companies, x represent the midpoint of the range of advertising expenditure.

y                                       f                      x                  fx                    fx²

$20 to under $30            9                     25               225               5625

$30 to under $40            13                    35               455               15925

$40 to under $50            21                    45               945              42525

$50 to under $60            18                    55               990              54450

$60 to under $70            14                     65               910               59150

                                       n = 75                           \sum fx = 3525      

\sum fx^2 = 177675

Mean, \bar{X} = \frac{\sum fx}{n}

\bar{X} = \frac{3525}{75} \\\bar{X} = 47

Standard Deviation:

SD = \sqrt{\frac{n \sum fx^2 - (\sum fx)^2}{n(n-1)} } \\SD = \sqrt{\frac{(75*177675) - (3525)^2}{75(75-1)} }\\SD = 12.73

Median:

Get the cumulative frequencies(cf)

         y                                        f                                cf

$20 to under $30                     9                                9

$30 to under $40                     13                               22

$40 to under $50                     21                               43

$50 to under $60                     18                               61

$60 to under $70                      14                              75

                                                N = 75

Median = Size of (N/2)th item

Median = Size of (75/2)th item

Median = Size of (37.5)th item

The median class = 40 to under 50

Lower limit, L₁ = 40

Cumulative frequency, cf = 22

f = 21

Class Width, h = 10

Median = L_1 + \frac{ (N/2) - cf}{f} * h\\

Median = 40 + \frac{ (75/2) - 22}{21} * 10\\

Median = 47.38

8 0
3 years ago
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