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netineya [11]
3 years ago
13

PLEASE HELP PAY NOT ATTENTION TO 27 where it’s blue accidentally pressed it and the blue won’t go away but PLEASE HELP

Mathematics
2 answers:
lianna [129]3 years ago
5 0

answer: b:30


step by step explanation: it none of the others because the numbers dont add up

Temka [501]3 years ago
3 0
B) 30

3p = 18
1p = 6
5p = 30
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Police Chase: A speeder traveling 40 miles per hour (in a 25 mph zone) passes a stopped police car which immediately takes off a
zubka84 [21]

Answer:

a. 18.34 s b. 327.92 m

Step-by-step explanation:

a. How long before the police car catches the speeder who continued traveling at 40 miles/hour

The acceleration of the car a in 10 s from 0 to 55 mi/h is a = (v - u)/t where u = initial velocity = 0 m/s, v = final velocity = 55 mi/h = 55 × 1609 m/3600 s = 24.58 m/s and t = time = 10 s.

So, a =  (v - u)/t =  (24.58 m/s - 0 m/s)/10 s = 24.58 m/s ÷ 10 s = 2.458 m/s².

The distance moved by the police car in 10 s is gotten from

s = ut + 1/2at² where u = initial velocity of police car = 0 m/s, a = acceleration = 2.458 m/s² and t = time = 10 s.

s = 0 m/s × 10 s + 1/2 × 2.458 m/s² (10)²

s = 0 m + 1/2 × 2.458 m/s² × 100 s²

s = 122.9 m

The distance moved when the police car is driving at 55 mi/h is s' = 24.58 t where t = driving time after attaining 55 mi/h

The total distance moved by the police car is thus S = s + s' = 122.9 + 24.58t

The total distance moved by the speeder is S' = 40t' mi = (40 × 1609 m/3600 s)t' =  17.88t' m where t' = time taken for police to catch up with speeder.

Since both distances are the same,

S' = S

17.88t' = 122.9 + 24.58t

Also, the time  taken for the police car to catch up with the speeder, t' = time taken for car to accelerate to 55 mi/h + rest of time taken for police car to catch up with speed, t

t' = 10 + t

So, substituting t' into the equation, we have

17.88t' = 122.9 + 24.58t

17.88(10 + t) = 122.9 + 24.58t

178.8 + 17.88t = 122.9 + 24.58t

17.88t - 24.58t = 122.9 - 178.8

-6.7t = -55.9

t = -55.9/-6.7

t = 8.34 s

So, t' = 10 + t

t' = 10 + 8.34

t' = 18.34 s

So, it will take 18.34 s before the police car catches the speeder who continued traveling at 40 miles/hour

b. how far before the police car catches the speeder who continued traveling at 40 miles/hour

Since the distance moved by the police car also equals the distance moved by the speeder, how far the police car will move before he catches the speeder is given by S' = 17.88t' = 17.88 × 18.34 s = 327.92 m

4 0
2 years ago
John find 1/5 of the bar chocolate he bought was already eaten by his brother. He eat 3/4 of what was remaining. Find the portio
larisa86 [58]

Answer:

1/5 is left.

Step-by-step explanation:

Portion remaining after the bar was eaten by his brother = 1 - 1/5 = 4/5.

Portion remaining after John ate 3/4 of this = 4/5 - 3/4* 4/5 = 4/5 - 3/5

=  1/5.

3 0
3 years ago
Is π^2 greater or less than 7.2?
STatiana [176]

Answer:

less than

Step-by-step explanation:

Well pi divided by 2 is 1.57 and you need to figure out if 7.2 is greater than or less than pi^2 aka 1.57 so theres your ansewr

4 0
2 years ago
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What percent of 180 is 45
Neporo4naja [7]

Answer:

81

Step-by-step explanation:

:)

5 0
2 years ago
What's the difference?
Komok [63]
\bf \begin{cases}
(-2x^2)\\
-2x^2
\end{cases}\qquad (-2x^2)-(-2x^2)\implies -2x^2+2x^2\implies ? you tell us
3 0
3 years ago
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