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Tomtit [17]
2 years ago
6

A business buys a computer for $3,000. After 4 years the value of the computer is expected to be $250. The value, v, can be rela

ted to the time in years, t, in a linear equation. Which equation models the relationship between v an t?
a.v=250t
b.v=-250t
c.v=687.50t-3,000
d.v=-687.50t+3,000
Mathematics
1 answer:
yuradex [85]2 years ago
6 0

You are given two points in the linear function. At time 0 years, the value is $3000. At time 4 years, the value is $250. This means you have points (0, 3000) and (4, 250). You need to find the equation of the line that passes through those two points.

y = mx + b

m = (y2 - y1)/(x2 - x1) = (3000 - 250)/(0 - 4) = 2750/(-4) = -687.5

Use point (0, 3000).

3000 = -687.5(0) + b

b = 3000

The equation is

y = -687.5x + 3000

Since we are using points (t, v) instead of (x, y), we have:

v = -687.5t + 3000

Answer: d. v = -687.50 t + 3,000

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Hello!

Lynne invested 35,000 into an account earning 4% annual interest compounded quarterly she makes no other deposits into the account and does not withdraw any money. What is the balance of Lynne's account in 5years

Data:

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We have the following compound interest formula

P' = P*(1+\dfrac{r}{n})^{nt}

P' = 35000*(1+\frac{0,04}{4})^{4*5}

P' = 35000*(1+0,01)^{20}

P' = 35000*(1,01)^{20}

P' = 35000*(1.22019003995...)

P' \approx 42,706.66

So the new principal P' after 5 years is approximately $42,706.66.  

Subtracting the original principal from this amount gives the amount of interest received:

P' - P = I

42,706.66 - 35000 = \boxed{\boxed{7,706.66}}\end{array}}\qquad\checkmark

________________________

I Hope this helps, greetings ... Dexteright02! =)

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