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dem82 [27]
3 years ago
11

What is the sum of the arithmetic sequence 3, 9, 15..., if there are 36 terms? (5 points)

Mathematics
1 answer:
nikklg [1K]3 years ago
8 0
The answer is 3,888 !!!!!!!!
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Calculate the slope of a line the -1,2 and 0,8
krok68 [10]

\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{8}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{8}-\stackrel{y1}{2}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-1)}}}\implies \cfrac{6}{0+1}\implies 6

4 0
3 years ago
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Parallel to y =9x 3, y-intercept at -2
Mashutka [201]
Slope-intercept form:
y=mx+b
m=slope
b=y-intercept

We have this line: y=9x+3; a line parallel to this line (y=9x+3) will have the same slope; therefore m would be equal to 9 (m=9).

Data:
m=9
b=-2
y=mx+b
y=9x-2

Answer: y=9x-2
3 0
3 years ago
What is (6,2) rotation 270
nignag [31]

Given:

The point is (6,2).

To find:

The image of given point after rotation of 270 degrees.

Solution:

Let the given point be P(6,2).

Rotation of 270 degrees means the figure is rotated 270 degrees counterclockwise about the origin. So, the rule of rotation is

(x,y)\to (y,-x)

Using this rule, we get

P(6,2)\to P'(2,-6)

Therefore, the image of given point is (2,-6).

3 0
3 years ago
a bank offers an annual simple interest rate of 8% on Home Improvement loans, Tobias borrowed $17,000 over a period of 2 years.
shepuryov [24]
The answer would be $19,270.
Steps: 
1. Take 17,000 and multiply by 8%.
2. Take the sum of that which is $1,360 and multiply by two (for the two years).
3.The sum of that would be $2,720 and add onto $17,000.
4. The sum of that would be $19,270!
7 0
3 years ago
How does the graph of f(x)=3lx+2l+4 relate to its parent function?
Sergeeva-Olga [200]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}

now, with that template above in mind, let's see this one

\bf parent\implies f(x)=|x|
\\\\\\
\begin{array}{lllcclll}
f(x)=&3|&1x&+2|&+4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}


A=3, B=1,  shrunk by AB or 3 units, about 1/3
C=2,          horizontal shift by C/B or 2/1 or just 2, to the left
D=4,          vertical shift upwards of 4 units

check the picture below

7 0
2 years ago
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