The product of r and 9 divided by 2 is equal to 27 what is the value of r?

10 + x + 5x²-x- 3 +5x<br> Which is the simplified expression found by combining like terms?

zlopas [31]

The answer is 5x^2 + 5x + 7

6 0

3 years ago

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Solve for xxx. Write the smaller solution first, and the larger solution second.

____ [38]

Answer:

$x=-5\text{ or }x=2$

Step-by-step explanation:

We have been given an equation $x^2+3x-10=0$ . We are asked to find the solutions of our given equation.

We will use splitting the middle term method to solve quadratic equation.

We will split middle term of our given equation into parts such that whose product is $-10$ and whose sum is 3.

We know that such two numbers are $5\text{ and }-2$ .

$x^2+5x-2x-10=0$

$(x^2+5x)+(-2x-10)=0$

$x(x+5)-2(x+5)=0$

$(x+5)(x-2)=0$

Using zero product property, we will get:

$(x+5)=0\text{ or }(x-2)=0$

$x+5=0\text{ or }x-2=0$

$x=-5\text{ or }x=2$

Therefore, the solutions for our given equation are $x=-5\text{ or }x=2$ .

4 0

3 years ago

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The original price of a sweatshirt is $50. The sale price is 75% off the original price. Find the sale price of the sweatshirt.

Julli [10]

Answer:

$87.5

Step-by-step explanation:

Original price also means COST PRICE

C.P=$50

S.P=75% of $50-$50

To find the sale price it will be 75% of C.P -C.P

75% × $50 + $50= 0.75 × $50-$50

=$37.5-$50.

= $12.5

therefore the sale price is $12.5

THANK YOU

6 0

2 years ago

A sample of 5 buttons is randomly selected and the following diameters are measured in inches. Give a point estimate for the pop

Helen [10]

Answer:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

Step-by-step explanation:

For this case we have the following data:

1.04,1.00,1.13,1.08,1.11

And in order to estimate the population variance we can use the sample variance formula:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

3 0

4 years ago

Find x in the parallelogram OA =(X+23) IN ; OC=31 in

ddd [48]

82 Europe dduuxhxxhhchcch

3 0

3 years ago