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2 years ago

Write two point-slope equations for the line passing through the points (6, 5) and (3, 1)

Mathematics

2 answers:

Lady_Fox [76]2 years ago

6 0

Answer:

Point-slope equations:

y - 5 = 4/3 (x - 6)

y - 1 = 4/3 (x - 3)

Step-by-step explanation:

Given two coordinate points (6, 5) and (3, 1)

Slope = (5 - 1)/(6 - 3) = 4/3

Point-slope equations:

y - 5 = 4/3 (x - 6)

y - 1 = 4/3 (x - 3)

Anvisha [2.4K]2 years ago

3 0

Answer:

idkh yvyogug7ubuhu yvvvyvuvuvuvyvyvyvubj

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Determine whether the given function is a solution to the given differential equation. y=cosx+x8, d^2y/dx^2 + y = x^8 + 56x^6.

Ulleksa [173]

The correct question is:

Determine whether the given function is a solution to the given differential equation. y = cosx + x^8; d²y/dx² + y = x^8 + 56x^6

Step-by-step explanation:

Given the differential equation

d²y/dx² + y = x^8 + 56x^6.

Suppose y = cosx + x^8 is a solution, then differentiating y twice, and adding it to itself, must give the value on the right hand side of the differential equation.

Let us differentiate y twice

y = cosx + x^8

dy/dx = -sinx + 8x^7

d²y/dx² = -cosx + 56x^6

Now,

d²y/dx² + y = -cosx + 56x^6 + cosx + x^8

= 56x^6 + x^8

Therefore,

d²y/dx² + y = x^8 + 56x^6

Which shows that y = cosx + x^8 is a solution to the differential equation.

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3 years ago

Which of the following would be the last step in evaluating the problem 7+5(6-2)%2

salantis [7]

Answer:

7+5(6-2)%2

7+20%2

7+40%

7.4

5 0

2 years ago

Jane needs to memorize words on a vocabulary list for Korean class. She has 18 words to memorize, and she is two-thirds done. Ho

alexgriva [62]

2/3 of 18...." of " means multiply
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3 years ago

On Texas Avenue between University Drive and George Bush Drive, accidents occur according to a Poisson process at a rate of thre

Zarrin [17]

Answer:

(a) The probability is 0.6514

(b) The probability is 0.7769

Step-by-step explanation:

If the number of accidents occur according to a poisson process, the probability that x accidents occurs on a given day is:

$P(x)=\frac{e^{-at}*(at)^{x} }{x!}$

Where a is the mean number of accidents per day and t is the number of days.

So, for part (a), a is equal to 3/7 and t is equal to 1 day, because there is a rate of 3 accidents every 7 days.

Then, the probability that a given day has no accidents is calculated as:

$P(x)=\frac{e^{-3/7}*(3/7)^{x}}{x!}$

$P(0)=\frac{e^{-3/7}*(3/7)^{0}}{0!}=0.6514$

On the other hand the probability that February has at least one accident with a personal injury is calculated as:

P(x≥1)=1 - P(0)

Where P(0) is calculated as:

$P(x)=\frac{e^{-at}*(at)^{x} }{x!}$

Where a is equivalent to (3/7)(1/8) because that is the mean number of accidents with personal injury per day, and t is equal to 28 because 4 weeks has 28 days, so:

$P(x)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{x}}{x!}$

$P(0)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{0}}{0!}=0.2231$

Finally, P(x≥1) is:

P(x≥1) = 1 - 0.2231 = 0.7769

3 0

3 years ago

❤️❤️help please ASAP

Archy [21]

From what i see, i guess the answer may be B. it looks like it, but i dont really know.

6 0

3 years ago

Read 2 more answers