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3 years ago

Please help this is a test I need help quick

Mathematics

1 answer:

RoseWind [281]3 years ago

8 0

Answer:

Parallel is 3

Perpendicular is - 1/3

Step-by-step explanation:

Good luck!

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What are the coordinates of your new IMAGE A’B’C’? A’=____ B’=____ C’=____

natita [175]

Answer:

Sensor Calibration

Convert between coordinate systems of every sensor, image, vehicle and global coordinate axis system. So data from a sensor can be mapped globally.

Calibration of a camera helps to convert a pixel in an image to

Computer Vision

Step-by-step explanation:

3 0

3 years ago

What is the derivative of 1/square root 4x.

Bumek [7]

Answer:

$\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{-1}{4x^\bigg{\frac{3}{2}}}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Exponential Properties

Exponential Property [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Property [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

Step 1: Define

Identify.

$\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg]$

Step 2: Differentiate

Simplify: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \bigg( \frac{1}{2\sqrt{x}} \bigg)'$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( \frac{1}{\sqrt{x}} \bigg)'$
Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( \frac{1}{x^\Big{\frac{1}{2}}} \bigg)'$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( x^\bigg{\frac{-1}{2}} \bigg)'$
Derivative Rule [Basic Power Rule]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( \frac{-1}{2} x^\bigg{\frac{-3}{2}} \bigg)$
Simplify: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{-1}{4} x^\bigg{\frac{-3}{2}}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{-1}{4x^\bigg{\frac{3}{2}}}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

5 0

3 years ago

Which number is missing from the table of equal ratios?

Elodia [21]

Answer:

your answer is option (c) 105

3 0

3 years ago

Read 2 more answers

When a number is written in scientific notion, how can you tell right away whether or not it is or than or equal to one?

nikklg [1K]

Well, to know right away whether or not a number is equal to 1, you need to know what 1 is in scientific notation. 1 * 10^0. Easy enough :) To know if the number is greater than one, any positive number multiplied by 10^a number higher than 0 is greater than one. As well as any number greater than one multiplied by 10^0 or a positive number. For numbers less than one, the way to know is if the number is being multiplied by 10 ^ a negative number. I hope this helps :)

8 0

4 years ago

C.) y=x2 + 4x - 1 a= b = c. Vertex Axis of Symmetry:

Savatey [412]

Answer:

a=1

b=4

c=-1

Axis of cemetry and vertex:x=-2

Step-by-step explanation:

x=-b/2a

x=-4/2(1)

x=-2

3 0

4 years ago