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kirill115 [55]
4 years ago
12

I'm stuck could you help? :)

Mathematics
1 answer:
harina [27]4 years ago
4 0
Its b because even though she rounded 57.25 to 60, she rounded 28 to 20, which she rounded it wrong, and 60 divided by 20 is 3 and that's how she got to think that the answer was around 3.00.
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 (Do it if you want BRAINLY) The original height of Khafre's pyramid, next to the Great Pyramid, was about 471 ft. Each side of
Lesechka [4]

We have the base measurement for the triangles composing the sides. We need their altitude.  

Imagine a right triangle with these sides:  

(1) from the apex of the pyramid to the point on the base directly underneath it (471 ft);  

(2) from the middle of base edge to the point underneath the apex (half of 708 ft = 354 ft);  

(3) the hypotenuse, the altitude of a triangular side.  

Using the Pythagorean Theorem, we find the hypotenuse to be  

√(471^2 + 354^2) = about 589.2 feet  

Now we add up the four triangles' areas. Each is base * altitude / 2, so:  

4 x 708 x 589.2 / 2  

= 2 x 708 x 589.2  

= 834,307.2 square feet, the lateral area.

7 0
4 years ago
Please help me with this ​
Zina [86]

Answer:

1.Triangle is heavier than a square.

2.Circle is lighter than the triangle and square.

3.3 squares won't be balanced between one triangle.

Step-by-step explanation:

Imagine Triangle is 10 and Square is 3

Triangle is heavier.

Imagine Circle is 1

3+3+3=9 also 3 squares

3 squares + 1 circle = 10

as one circle equals 1.

3 0
3 years ago
If the water level at the lake continued to change at the lake rate for 3 months in a row, explain how you could estimate the to
Temka [501]
Multiple it by the unite rate of change
5 0
3 years ago
I need help!
blagie [28]

Here is the solution...

1) \sqrt[3]{135} \\

Solution

We can rewrite \sqrt[3]{135} = \sqrt[3]{27} *\sqrt[3]{5}

Here, \sqrt[3]{27} = 3

Now substitute the value, we get

\sqrt[3]{135} = 3 \sqrt[3]{5}

The answer is 3\sqrt[3]{5}


2) -5\sqrt[3]{40} Solution[tex]-5\sqrt[3]{40} = -5\sqrt[3]{8} *\sqrt[3]{5}

Here \sqrt[3]{8} = \sqrt[3]{2^{3} } = 2\\

Therefore, we get -5*2\sqrt[3]{5} = -10 \sqrt[3]{5}

The answer is-10 \sqrt[3]{5}[/tex]


2) 2\sqrt[3]{5} * 4\sqrt[3]{8}

Solution

\sqrt[3]{8} = 2

Now plug in the above in the given expression, we get

2\sqrt[3]{5} * 4*2 = 16\sqrt[3]{5}                         {2*4*2 = 16]

The answer is 16\sqrt[3]{5}

8 0
3 years ago
A. 25<br> B.20<br> C.1<br> D.1/5
spin [16.1K]
Answer: B.20


Step 1: Understand the graph

In the graph provided, each line goes up by 10 on the y-axis, with the graph marking each 50. On the x-axis, every 5 lines is equal to 1, as indicated on the graph.

Step 2: Find the unit rate

To find the unit rate, we need to find where the line hits 1 on the x-axis. To do so, go to one on the x-axis, and go up until you find where the line hits. Then we see the value on the y-axis to know the unit rate. In this case, it is on the second line above. Since we established in step 1 that each line is equal to 10 on the y-axis, we know that the two lines will be equal to 20.

This is your answer! The unit rate is 20. Hope this helps! Comment below for more questions.
3 0
3 years ago
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