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4 years ago

I'm stuck could you help? :)

Mathematics

1 answer:

harina [27]4 years ago

4 0

Its b because even though she rounded 57.25 to 60, she rounded 28 to 20, which she rounded it wrong, and 60 divided by 20 is 3 and that's how she got to think that the answer was around 3.00.

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(Do it if you want BRAINLY) The original height of Khafre's pyramid, next to the Great Pyramid, was about 471 ft. Each side of

Lesechka [4]

We have the base measurement for the triangles composing the sides. We need their altitude.

Imagine a right triangle with these sides:

(1) from the apex of the pyramid to the point on the base directly underneath it (471 ft);

(2) from the middle of base edge to the point underneath the apex (half of 708 ft = 354 ft);

(3) the hypotenuse, the altitude of a triangular side.

Using the Pythagorean Theorem, we find the hypotenuse to be

√(471^2 + 354^2) = about 589.2 feet

Now we add up the four triangles' areas. Each is base * altitude / 2, so:

4 x 708 x 589.2 / 2

= 2 x 708 x 589.2

= 834,307.2 square feet, the lateral area.

7 0

4 years ago

Please help me with this

Zina [86]

Answer:

1.Triangle is heavier than a square.

2.Circle is lighter than the triangle and square.

3.3 squares won't be balanced between one triangle.

Step-by-step explanation:

Imagine Triangle is 10 and Square is 3

Triangle is heavier.

Imagine Circle is 1

3+3+3=9 also 3 squares

3 squares + 1 circle = 10

as one circle equals 1.

3 0

3 years ago

If the water level at the lake continued to change at the lake rate for 3 months in a row, explain how you could estimate the to

Temka [501]

Multiple it by the unite rate of change

5 0

3 years ago

I need help!

blagie [28]

Here is the solution...

1) $\sqrt[3]{135} \\$

Solution

We can rewrite $\sqrt[3]{135} = \sqrt[3]{27} *\sqrt[3]{5}$

Here, $\sqrt[3]{27} = 3$

Now substitute the value, we get

$\sqrt[3]{135} = 3 \sqrt[3]{5}$

The answer is $3\sqrt[3]{5}$

2) $-5\sqrt[3]{40} Solution[tex]-5\sqrt[3]{40} = -5\sqrt[3]{8} *\sqrt[3]{5}$

Here $\sqrt[3]{8} = \sqrt[3]{2^{3} } = 2\\$

Therefore, we get $-5*2\sqrt[3]{5} = -10 \sqrt[3]{5}$

The answer is-10 \sqrt[3]{5}[/tex]

2) $2\sqrt[3]{5} * 4\sqrt[3]{8}$

Solution

$\sqrt[3]{8} = 2$

Now plug in the above in the given expression, we get

$2\sqrt[3]{5} * 4*2 = 16\sqrt[3]{5}$ {2*4*2 = 16]

The answer is $16\sqrt[3]{5}$

8 0

3 years ago

A. 25<br> B.20<br> C.1<br> D.1/5

spin [16.1K]

Answer: B.20

Step 1: Understand the graph

In the graph provided, each line goes up by 10 on the y-axis, with the graph marking each 50. On the x-axis, every 5 lines is equal to 1, as indicated on the graph.

Step 2: Find the unit rate

To find the unit rate, we need to find where the line hits 1 on the x-axis. To do so, go to one on the x-axis, and go up until you find where the line hits. Then we see the value on the y-axis to know the unit rate. In this case, it is on the second line above. Since we established in step 1 that each line is equal to 10 on the y-axis, we know that the two lines will be equal to 20.

This is your answer! The unit rate is 20. Hope this helps! Comment below for more questions.

3 0

3 years ago