Question

Which function in vertex form is equivalent to f(x) = x2 + 6x + 3?

Answer 1

(-3, -6)
(sorry, the other calculator does the answers, but not the one i'm using right now!)

Answer 2

Answer:

$y=(x+3)^{2}-6$

Step-by-step explanation:

Let's find the answer using the following method:

The original quadratic function is $f(c)=x^{2}+6x+3$

The vertex form of a quadratic equation is:

$y=(x-h)^{2}+k$

where (h,k) is the vertex which can be found as:

$h=\frac{-b}{2a} =\frac{-6}{2*1}=-3\\h=f(h)=(-3)^{2}+(6*(-3))+3 = -6$

So the vertex form is:

$y=(x+3)^{2}-6$