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3 years ago

How did Dalton explain the formation of compounds

Chemistry

1 answer:

Darya [45]3 years ago

5 0

Atoms chemically combine

hope this helps!

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A sample of argon gas at 55°C is under 845 mm Hg pressure. What will the new temperature be if the pressure is raised to 1050 mm

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Answer:

The final temperature at 1050 mmHg is 134.57 $^{\circ}C$ or 407.57 Kelvin.

Explanation:

Initial temperature = T = 55 $^{\circ}C$ = 328 K

Initial pressure = P = 845 mmHg

Assuming final to be temperature to be T' Kelvin

Final Pressure = P' = 1050 mmHg

The final temperature is obtained by following relation at constant volume

$\displaystyle \frac{P}{P'}=\displaystyle \frac{T}{T'} \\ \displaystyle \frac{845 \textrm{ mmHg}}{1050 \textrm{ mmHg}} = \displaystyle \frac{328 \textrm{ K}}{T'} \\T' = 407.57 \textrm{ Kelvin}$

The final temperature is 407.57 K

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4 years ago

If 60.0 ml of a 1.5 m hcl solution is put into a flask and diluted with water to make 2.0 l of solution

77julia77 [94]

Answer:

The molarity of the diluted HCl solution: M₂ = 0.045 M

Explanation:

To find- the molarity of the diluted HCl solution (M₂)

Given- For original HCl solution-

Molarity: M₁ = 1.5 M, Volume: V₁ = 60.0 ml = 0.06 L (∵ 1L = 1000 mL)

Then this original solution is diluted to a volume of 2 L

Thus for the diluted HCl solution-

The Volume of the diluted HCl solution: V₂ = 2 L

So the Molarity of the diluted HCl solution (M₂) can be calculated by the dilution equation:

$M_{1}\times V_{1} = M_{2}\times V_{2}$

$\Rightarrow M_{2} = \frac{M_{1}\times V_{1}}{V_{2}}$

$\Rightarrow M_{2} = \frac{1.5 M\times 0.06 L}{2 L} = 0.045 M$

Therefore, the molarity of the diluted HCl solution: M₂ = 0.045 M

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3 years ago

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Answer:

The cell division in which number of chromosome remain same is mitosis and in it is reduced to half is mieosis.

Explanation:

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Under which conditions would the solubility of a gas be greatest? A. high pressure and high temperature B. high pressure and low

LiRa [457]

Answer:

High pressure and low temperature.

Explanation:

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3 years ago

How did Dalton explain the formation of compounds​

How did Dalton explain the formation of compounds