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3 years ago

What other means of qualitative analysis are used to identify metals

Chemistry

2 answers:

NNADVOKAT [17]3 years ago

5 0

Answer:

Precipitation, visible-evidenced redox reactions and complexation reactions are used to identify metals.

Explanation:

Hello,

In this case, since you are talking about qualitative analysis, several techniques such as precipitation, visible-evidenced redox reactions and complexation reactions are suitable to identify metals. Such reactions are good enough as long as depending on the metals' cation, it precipitate, redox behavior and complexation will produce a particular color that will allow the identification of the metal.

For instance, to determine the presence of silver, a white precipitate is obtained when chloride ions are placed into a silver-containing sample. The presence of cobalt is substantiated via the formation of a yellowish-brown ionic complex of hexamminecobaltae (II).

Best regards.

Masja [62]3 years ago

3 0

<span>Figure out the density. every metal has it's own. just fill a glass up to the top with water, and then carefully put the metal in. measure how much water is displaced (either by collecting the water or by measuring the glass afterwards),
then you will have the substance's density, because you have volume and it's measurement. </span>

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Balance the following skeleton reactions and identify the oxidizing and reducing agents:(b) CrO₄²⁻(aq) + Cu(s) → CrOH₃(s) + CuOH

andrew-mc [135]

The balanced skeleton reactions are given below

2CrO₄²⁻(aq) + 3Cu(s) +8 $H_{2} O$ (l) → 2Cr(OH)₃(s) + 3Cu(OH)₂(s) + 6 $OH^{-}$ (aq)

The oxidising agent and reducing agents are Cr and Cu .

There are following steps involve in balance redox reaction in basic medium .

First divide the reaction into two half reactions which give oxidation and reduction half reaction.

Then balance the elements other than oxygen and hydrogen atom.

Balance the oxygen atom by adding $H_{2} O$ where number of oxygen is less .

Balance the hydrogen atom by adding $H^{+}$ on another side of where water molecule added.
Add $OH^{-}$ ions to both sides to neutralize $H^{+}$ ion.
Combine $H^{+}$ and $OH^{-}$ ion to make $H_{2} O$ .

Balance the charge by adding $e^{-}$ .

Add the half reaction .

The species which reduces the other species in the redox reaction is called oxidizing agent . Similarly , the species which oxidize the other species in the redox reaction is called reducing agent .

To learn more about reducing agents please click here ,

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1 year ago

A Rolaids tablet contains calcium for neutralizing stomach acid. if a Rolaids tablet neutralizes 24.65ml of 0.547m hydrochloric

Lelu [443]

There are 674 mg of calcium carbonate in a Rolaids tablet

<h3>Further explanation</h3>

Reaction

CaCO₃ + 2HCl ⇒ CaCl₂ + CO₂ +H₂O

V HCl = 24.65 ml

M HCl = 0.547

mol HCl :

$\tt 24.65\times 0.547=13.48~mlmol$

ratio mol CaCO₃ : HCl = 1 : 2, so mol CaCO₃ :

$\tt \dfrac{1}{2}\times 13.48=6.74~mlmol=6.74\times 10^{-3}~mol$

mass of CaCO₃ (MW=100~g/mol) :

$\tt 6.74\times 10^{-3}\times 100=0.674~g=674~mg$

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