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Vlad [161]
3 years ago
8

The matter in this series of images is going through a change. Draw a conclusion about the type of change shown. Is it a physica

l change or a chemical change? Explain your reasoning by providing evidence.

Chemistry
1 answer:
34kurt3 years ago
8 0

Answer:

This is a chemical change because it has been lit on fire. When it is lit on fire, the fire has been made, heat has been made, and gasses produced from the fire have also been made. Because this introduces new matter to the pictures, it is a chemical reaction.

Explanation:

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How would you make 5mls of a solution that is 2.0% lactose and 0.1M SPG buffer from separate stock solutions that are 6% lactose
Aliun [14]

Answer:

Check the explanation section.

Explanation:

The following steps should be followed orderly.

STEP ONE:

Use the dilution equation in the calculation of the volume for the stock solution. That is, C1 × V1 = C2 × V2.

Where C1 and C2 are the concentration of the stock solution and the diluted solution.

STEP TWO:

Put 6% of lactose and make sure to dilute it in order to make 2.0% lactose

and put it in Beaker A. Also, make sure to dilute the 1M to 0.1M SPG buffer in Beaker B.

STEP TWO:

Now, from beaker A containing 2% lactose, measure and remove 5.0 mL from it. Also, measure and remove 5.0 mL from beaker B containing 0.1M SPG.

So, in STEP TWO above we won't know how much water we need to use for dilution, thus, there is the need to make use of STEP ONE.

Therefore, from STEP ONE ABOVE, we have the dilution equation given as;

C1 × V1 = C2 × V2.

Hence, 6 × V1 = 2 × 5. Therefore, the volume needed from the stock solution, V1 = (2 × 5)/ 6 = 1.6 mL.

STEP THREE:

Now measure out 1.6 mL from the stock solution, that is 6% lactose and add it to 5mL of the diluted solution of 2% in beaker A into another container, say beaker C and add H2O to form SOLUTION X.

STEP FOUR:

Using the dilution equation again, Determine the the volume that is needed from 1M SPG.

C1 × V1 = C2 × V2.

V1 = ( 0.1 × 5)/ 1 = 0.5mL.

STEP FIVE:

measure 0.5mL out from the 1M SPG and 5 mL out of 0.1M SPG buffer and add water to it to form SOLUTION Y.

STEP SIX:

Now, mix solution X and solution Y together and take the required 5ml

7 0
3 years ago
can someone pleaseeee help me with this so basically do a food web with these animals ( the food web is supposed to look like th
dangina [55]

Answer:

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Explanation:

3 0
3 years ago
What is the molarity if 60.4 grams of hydrochloric acid was added to 505 mL of water?
ANTONII [103]

Answer:

3.29 M

Explanation:

Molarity refers to the molar concentration of a solution and it can be calculated using the formula below:

Molarity (M) = number of moles (n) ÷ volume (V)

According to this question, the mass of HCl was given to be 60.4 grams and the volume of water as 505 mL.

Using mole = mass/molar mass to convert mass of HCl to moles

Molar mass of HCl = 1.0079 + 35.453 = 36.4609g/mol

mole = 60.4g ÷ 36.4609g/mol

mole = 1.66mol

Volume of water = 505mL = 505/1000 = 0.505L

Molarity, M = 1.66 ÷ 0.505

Molarity of HCl solution = 3.29 M

8 0
3 years ago
Wat are the five assumption of kinetic therory of gases​
il63 [147K]

Answer:

The five assumption of Kinetic molecular theory are given below.

Explanation:

Kinetic molecular theory of gasses stated that,

1) Gases consist of large number of smaller particles which are distance apart from each others.

2) The gas molecules collide with each other and also with wall of container and this collision is elastic.

3) Gas molecules are in continuous random motion and posses kinetic energy.

4) The forces of attraction between gas molecules are very small and considered negligible.

5) The temperature of gas is directly proportional to average kinetic energy of gas molecules.

6 0
3 years ago
If you have 220 liters O2 at STP how many moles of O2 do you have
Ostrovityanka [42]

Answer: C

Explanation: I GOT IT RIGHT ON MY TEST DUDE AND MY TEACHER SAID IT WAS RIGHT TOO I GOT 100% BRO TRUST ME!

4 0
4 years ago
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