3 years ago

Please help me with this??

Mathematics

1 answer:

Lina20 [59]3 years ago

4 0

This problem is simple the correct choice for this problem will be a

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HELP PLEASE SOMEONE

Rom4ik [11]

$f(x)= \frac{x}{2} -2$ and $g(x)=2 x^{2} +x-3$
(f+g)(x) = $\frac{x}{2} -2+2 x^{2} +x-3$
combining like terms gives you answer choice B

8 0

3 years ago

3 / m + 4 - 4 / m = 6 (i) Show that this equation can be written as 6m^2 + 25m+16= 0

Evgen [1.6K]

Answer:

Proved Below

Step-by-step explanation:

$\sf \frac{3}{m+4} - \frac{4}{m} = 6\\LCM = m(m+4)\\Multiplying \ both \ sides \ by\ m(m+4)\\3m - 4(m+4) = 6m(m+4)\\3m-4m-16 = 6m^2+24m\\-m-16 = 6m^2+24m\\Adding\ m\ to\ both\ sides\\-16 = 6m^2+24m+m\\-16 = 6m^2+25m\\Adding \ 16 \ to \ both \ sides\\0 = 6m^2+25m+16\\OR\\6m^2+25m+16 = 0$