Answer:
The Chi-square test of independence
Step-by-step explanation:
The answer to this question is the Chi-square test of independence because it is what is used to determine the existence of an association between nominal/categorical variables. This test is non parametric in nature and it can also be called the chi square test of association.
The data is tabulated. each row is a representation of the category for one of the variables and each column is for the other variable.
If you were to cut a cake diagonally we could say the result would be an oval. Please refer to the image I provided below.
I didn't mean to post the answer and can't figure out how to take it down. Somebody report it so it does go down and the question can be later answered. Thank you
Answer:
vertical compression of One-half, horizontal stretch to a period of 4 pi, vertical shift of 1 unit up, phase shift of Pi units left
Step-by-step explanation:
