Answer:
If i have three moles of a gas at a pressure of 5.6 atm and a volume of 3 liters, what is the temperature ?
We have the following data:
n (number of moles) = 3 moles
P (pressure) = 5.6 atm
V (volume) = 12 L
T (temperature) = ? (in Kelvin)
R (gas constant) = 0.082 atm.L / mol.K
We apply the data above to the Clapeyron equation (gas equation), let's see:
Answer:
The temperature is approximately 205 Kelvin
The simplified answer is 4/5
Answer:
12:16
Step-by-step explanation:
28 split into two groups could be 12 : 16. To check the work, see if 3/4 is equal to 12/16. It is, so this is the accurate ratio, as 12 + 16 = 28 and 12/16 = 3:4.
Answer:
Discount Final Price Each
1/3 off $ 19.95. $ 13.30
Step-by-step explanation:
I think its 13.30
Answer:

Step-by-step explanation:
A polynomial written in decreasing order of the degree of its monomials ( or single term ) is called its standard form,
In polynomial,
,
Degrees are written in increasing order,
⇒ It is not written in standard form,
In polynomial,
,
Degrees are written in decreasing order,
⇒ It is written in standard form,
In polynomial,
,
There is no order of degrees,
⇒ It is not written in standard form,
In polynomial,
,
There is no order of degrees,
⇒ It is not written in standard form,