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Ede4ka [16]
3 years ago
8

The polynomial function F(x)= 2x^2 +4 has a critical point at which of the

Mathematics
1 answer:
Whitepunk [10]3 years ago
8 0
It will be (C) because you have to find the GCF first than simplify it and it gives you 2
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For the equation given below, evaluate y′ at the point (−2,−1).<br><br> 3xy−3x−12=0.
SSSSS [86.1K]

Answer:

Y'=3xy-3x-12

Y'=F(-2,-1)=0

Step-by-step explanation:

The function of the equation at the point (-2,-1)

is where the equation make the function go to zero:

Y'=3xy-3x-12

Y'=F(-2,-1)=[3(-2)(-1)]-[3(-1)]-12

F(-2,-1)=[6]-[-6]-12

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3 years ago
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FrozenT [24]

Answer:

no, because for x=-3, y would have to be -31

Step-by-step explanation:

boy oh boy (or girl oh girl) - you wrote this in a horrible, horrible format.

I can only guess what your problem and the fitting answer would be.

y = -2×x^2 + 3×x - 4

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and that is wrong. for (-3,-4) to be on the graph of the function, y would have to be -4 when using x=-3 in the function. but y = -31 for x= -3.

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Step-by-step explanation:

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Answer:

G is not TRUE.

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PYTHAGOREAN THEOREM

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So for A²,

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B²

C² - A²= B²

6 0
2 years ago
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