Answer:The line segment we are required to compute is the solid red line. Let's first compute the diagonal of the rectangle of sides 12 cm and 11 cm. This length is greater than the 12 cm side of the rectangle, so it confirms our initial guess, the longest line segment is 12.89 cm long.
Step-by-step explanation:
Answer:
Yes the trainer was successful in an attempt for lucky to gain weight.
Step-by-step explanation:
Lucky was a weak and thin body shaped person who came to a gym trainer to gain weight. The trainer started to guide Lucky that he has to go for supplements and heavy weight lifting in order to gain weight. After 3 month's of hard work lucky has finally gained weight from 55 kg to 88 kgs.
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Answer:
25°
Step-by-step explanation:
The relevant trig relation is ...
Sin = Opposite/Hypotenuse
sin(?) = 25/60
? = arcsin(25/60) ≈ 24.62°
The indicated angle is about 25°.
The probability that of the questions studied, all three were the test questions selected by the professor is 0.05.
<h3>How to find the probability?</h3>
We can find the probability by dividing the total number of favorable events by the total number of events.
The total number of events is given by
.
The total number of favorable events is given by
.
The probability is given by = Favorable events/Total number of events
= 
= 
= 
= 0.05
The probability that all three questions are selected by the professor for the test is found to be 0.05.
Therefore, we have found that the probability that of the questions studied, all three were the test questions selected by the professor is 0.05.
Learn more about probability here: brainly.com/question/251701
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Disclaimer: The question was incomplete, the complete question is attached below.
Question: A professor gave her students six essay questions from which she will select three for a test. A student has time to study for only three of these six questions. What is the probability that, of the questions studied, all three were the test questions selected by the professor?
12x - 56 = y. Hope it helps! :) If you could vote my answer as the brainiest, that would be awesome! :)