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ki77a [65]
3 years ago
6

kyra invested $400 at 3% for 3 years . lishshawn invested $500 at 4% for 2 years calculate who earn the most interest and how mu

ch more money they earned​
Mathematics
1 answer:
eimsori [14]3 years ago
6 0

Answer:

Okay, so a bit of math is involved, along with steps.

Step-by-step explanation:

Kyra invested $400 at 3% for 3 years. meaning 3% of $400 is 12. 400+12=

Year 1: $412

3% of 412=12.23+412=

Year 2: $424.23

3% of 424.23=12.7+423.23=

Year 3: $435.93

Kyra made $35.93 in investments.

Lishsawn invested $500 at 4% for 2 years. Meaning, 4% of $500 is 20. 500+20

Year 1: $520

4% of 520=20.8+520

Year 2: $540.8

Lishawn made $40.8 dollars in investments. Meaning that Lishawn made $4.87 more dollars

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Write down the fifth term of the sequence that has its nth term:
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a) 34

b) 30

Step-by-step explanation:

so the nth term is just the position on the term, so if u want to find the 5th term you just have to substitute 5 in for n and solve!

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Steve wants to know what the average ACT scores of students graduated from his high school is. He randomly selected 25 students
Mashutka [201]

Answer:

The 86% confidence interval for the population mean is (19.982, 23.018).

As we are using a sample to make an inference about the population mean, we use a confidence interval with a certain degree of confidence.

We are 86% confident that the true mean ACT scores is between 19.982 and 23.018.

Step-by-step explanation:

We have the information:

Sample size n= 20

Mean M=21.5

STD s=5.7

Min = 15

Max = 26

Population STD σ=4.6  

Confidence level = 86%

We have to calculate a 86% confidence interval for the mean.

The population standard deviation is know and is σ=4.6.

The sample mean is M=21.5.

The sample size is N=20.

As σ is known, the standard error of the mean (σM) is calculated as:

\sigma_M=\dfrac{\sigma}{\sqrt{N}}=\dfrac{4.6}{\sqrt{20}}=\dfrac{4.6}{4.4721}=1.0286

The t-value for a 86% confidence interval is z=1.476.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.476 \cdot 1.0286=1.518

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 21.5-1.518=19.982\\\\UL=M+t \cdot s_M = 21.5+1.518=23.018

The 86% confidence interval for the population mean is (19.982, 23.018).

As we are using a sample to make an inference about the population mean, we use a confidence interval with a certain degree of confidence.

We are 86% confident that the true mean ACT scores is between 19.98 and 23.02.

3 0
3 years ago
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