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3 years ago

7/10 ÷ 1/5 pls i need help

1 answer:

3 0

7/10 ÷ 1/5 = 3 1/2 because if you just find the reciprocal of the second number (in this case 1/5) and then simply multiply the two numbers straight across after you find the reciprocal, you will need to convert and simplify as needed, and then you get your answer.

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Eileen randomly chooses 15 seeds from the bag of flower seeds she has left over from last year, and 10 seeds from the bag she bo

amm1812

I believe it is D, stratified random sampling.
Hope this helps!!

5 0

4 years ago

Read 2 more answers

Pls help I don’t understand

dmitriy555 [2]

The answer is c. $\frac{46}{9}$

a. $\frac{11}{5}=2.2$ (2.2≠5.11) (2.2 is not equal to 5.11)

b. $5\frac{1}{8}=\frac{5}{8}$ or 0.625 (0.625≠5.11) (0.625 is not equal to 5.11)

c. $\frac{46}{9} =5.11$ (5.11=5.11) (5.11 is equal to 5.11)

Therefore c is the answer

4 0

3 years ago

Multiply (3x2-4x+5)(x2-3x+2)

Iteru [2.4K]

So with this, you can rewrite the equation as: $(3x^2\times x^2)+(3x^2\times -3x)+(3x^2\times 2)+(-4x\times x^2)+(-4x\times -3x)+(-4x\times 2)+(5\times x^2)+(5\times -3x)+(5\times 2)$

Firstly, solve the multiplication: $3x^4+(-9x^3)+6x^2+(-4x^3)+12x^2+(-8x)+5x^2+(-15x)+10$

Next, combine like terms, and <u>your answer will be: $3x^4-13x^3+23x^2-23x+10$ </u>

7 0

3 years ago

You are choosing between two different cell phone plans. The first plan charges a rate of 23 cents per minute. The second plan c

jenyasd209 [6]

Answer:

357 minutes

Step-by-step explanation:

I subtracted 9 cents/minute from the 23 cents/minute to get 14 cents to get the difference between the two per minute charges. I then divided the monthly cost of $49.95 by .14 to get 356.79... So if you used 357 minutes in a month, the second plan would be 3 cents cheaper at $82.08 (.09 x 357= 32.13 + 49.95), vs. the first plan costing $82.11 (.23 x 357). At 356 minutes the first plan would still be cheaper.

3 0

3 years ago

If the inspection division of a county weights and measures department wants to estimate the mean amount of

Amanda [17]

If inspection department wants to estimate the mean amount with 95% confidence level with standard deviation 0.05 then it needed a sample size of 97.

Given 95% confidence level, standard deviation=0.05.

We know that margin of error is the range of values below and above the sample statistic in a confidence interval.

We assume that the values follow normal distribution. Normal distribution is a probability that is symmetric about the mean showing the data near the mean are more frequent in occurence than data far from mean.

We know that margin of error for a confidence interval is given by:

Me= $z/2* ST/\sqrt{N}$

α=1-0.95=0.05

α/2=0.025

z with α/2=1.96 (using normal distribution table)

Solving for n using formula of margin of error.

$n=(z/2ST/Me)^{2}$

n= $(1.96*0.05)^{2} /(0.01)^{2}$

=96.4

By rounding off we will get 97.

Hence the sample size required will be 97.

Learn more about standard deviation at brainly.com/question/475676

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The given question is incomplete and the full question is as under:

If the inspection division of a county weights and measures department wants to estimate the mean amount of soft drink fill in 2 liters bottles to within (0.01 liter with 95% confidence and also assumes that standard deviation is 0.05 liter. What is the sample size needed?

7 0

2 years ago