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marshall27 [118]
3 years ago
8

Identify the coefficient. 13 + 2q = 56

Mathematics
2 answers:
IRISSAK [1]3 years ago
7 0

Answer:

2 is the coefficient

Step-by-step explanation:

Vilka [71]3 years ago
5 0
The answer is 21.5

2 x 21.5 = 43
13 + 43 = 56
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SOMEONE PLEASE HELP!!
BARSIC [14]

Answer:

21

Step-by-step explanation:

7 0
3 years ago
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Find the mode: 16,12,10,15,7,916
Airida [17]

The mode is the value from a given set of data that occurs most often. It is the data with the highest frequency.

Given:

16,12,10,15,7,9,16

Form the above data given;

Rearranging for easy identification, we have;

7,9,10,12,15,16,16

\begin{gathered} 7\text{ appears once} \\ 9\text{ appears once} \\ 10\text{ appears once} \\ 12\text{ appears once} \\ 15\text{ appears once} \\ 16\text{ appears twice} \end{gathered}

From the above, we can deduce that the mode is 16 because it appears the most often. It appears twice.

Therefore, the mode is 16.

4 0
1 year ago
A number n plus 8 is greater than 11.
Bumek [7]
N+8>11 is the answer you are looking for 

8 0
4 years ago
A car insurance company has determined that 8% of all drivers were involved in a car accident last year. Among the 15 drivers li
svetlana [45]

Answer:

There is an 11.3% probability of getting 3 or more who were involved in a car accident last year.

Step-by-step explanation:

For each driver surveyed, there are only two possible outcomes. Either they were involved in a car accident last year, or they were not. This means that we solve this problem using binomial probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem

15 drivers are randomly selected, so n = 15.

A success consists in finding a driver that was involved in an accident. A car insurance company has determined that 8% of all drivers were involved in a car accident last year.  This means that \pi = 0.08.

What is the probability of getting 3 or more who were involved in a car accident last year?

This is P(X \geq 3).

Either less than 3 were involved in a car accident, or 3 or more were. Each one has it's probabilities. The sum of these probabilities is decimal 1. So:

P(X < 3) + P(X \geq 3) = 1

P(X \geq 3) = 1 - P(X < 3)

In which

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{15,0}.(0.08)^{0}.(0.92)^{15} = 0.2863

P(X = 1) = C_{15,1}.(0.08)^{1}.(0.92)^{14} = 0.3734

P(X = 2) = C_{15,2}.(0.08)^{2}.(0.92)^{13} = 0.2273

So

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2863 + 0.3734 + 0.2273 = 0.887

Finally

P(X \geq 3) = 1 - P(X < 3) = 1 - 0.887 = 0.113

There is an 11.3% probability of getting 3 or more who were involved in a car accident last year.

5 0
3 years ago
A set designer builds a model of the stage and the different pieces of furniture on it. He uses a scale of 5 cm to 1 m. What is
Akimi4 [234]

5-1

5:1

for every 5 cm there is 1 m

ur welcome ;]


8 0
3 years ago
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