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3 years ago

Find the perimeter of triangle ABC With the vertices A( 1,-6), B(1,-3) , and C(-4,-6)

Mathematics

1 answer:

DENIUS [597]3 years ago

4 0

Answer:

Step-by-step explanation:

Hopefully this helps!

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X/4 + 16 =-32 (Find the value of x) *

Tcecarenko [31]

Answer:

-4

Step-by-step explanation:

x/4+16=-32

-32+16= -16

x/4=-16

-16/4= -4

x= -4

4 0

4 years ago

write two division problems related to the multiplication problem below. 8×(-2)=-16

Mrac [35]

We can write two division problems related the given equation as follows.

Division problem one :

Here 8 is in multiplication with -2 on the left side.

so when we bring this 8 on the right side, we will have to apply opposite operation of multiplication which is division.

so dividing (-16) by 8 on the right side, we have:

$-2=\frac{-16}{8}$

Division problem two :

Here -2 is in multiplication with 8 on the left side.

so when we bring this (-2) on the right side, we will have to apply opposite operation of multiplication which is division.

so dividing (-16) by (-2) on the right side, we have:

$8=\frac{-16}{-2}$

7 0

3 years ago

The teacher does not have to spend all $36. Write an inequality relating 36 and 9 (7 - x) representing this situation. (Copy/pas

kotykmax [81]

Answer:

Step-by-step explanation:

From the question, we are to relate the amount the teacher spent to the expression 9(7-x).

Since the teacher does not have to spend all the $36, this means that he spent amount less than $36 but not equal to $36. Hence the best inequality sign that relates both expression is a less than sign (<) as shown;

9(7-x) < 36

hence the required inequality is 9(7-x) < 36

4 0

3 years ago

Please answer! I need it for my Math Homework.

Setler [38]

Here are the areas of the 3 separate shapes:

1. 27.5 m^2

2. 25.5 m^2

3. 27.5 m^2

As you can see, the 1st and 3rd shapes share the same total area, so those are the shapes you should select.

6 0

3 years ago

Help please ! thank u sm

astraxan [27]

Given:

The figure of triangle LNM.

To find:

The Law of Sines for the given triangle.

Solution:

Law of sines: In triangle ABC,

$\dfrac{\sin A^\circ}{a}=\dfrac{\sin B^\circ}{b}=\dfrac{\sin C^\circ}{c}$

Similarly, the Law of Sines for the given triangle LNM is:

$\dfrac{\sin L^\circ}{l}=\dfrac{\sin N^\circ}{n}=\dfrac{\sin M^\circ}{m}$

Therefore, the correct option is b.

7 0

3 years ago