Answer:
The area of the associated sector is
Step-by-step explanation:
step 1
Find the radius of the circle
we know that
The circumference of a circle is equal to

we have

substitute and solve for r


step 2
Find the area of the circle
we know that
The area of the circle is equal to

we have

substitute

step 3
Find the area of the associated sector
we know that
subtends the complete circle of area 
so
by proportion
Find the area of a sector with a central angle of 

The term (2 + 8) is described as the total amount of pieces of fabric. It makes it easier to put this term this way so you wouldn't have to do (8 x 5) + (2 x 5) and do the distributive property.
Find the median of each set:-
Median is middle number of a data set. If a data set has an odd number of numbers then the median is the middle number when ordered form least to greatest but if its an even number you have to find the mean for the middle 2 numbers when ordered for least to greatest.
A.
1.2, 2.4, 3.2, 3.2, 3.6, 4.0, 4.1, 4.7
Even numbers = 8
3.2 + 3.6 = 6.8
6.8 ÷ 2 =
Median = 3.4
So this shows that A isn't the answer because the median of A is 3.4, not 3.2.
B.
1.6, 2.8, 2.9, 3.1, 3.3, 3.6, 4.2, 4.5
Even numbers = 8
3.1 + 3.3 = 6.4
6.4 ÷ 2 = 3.2
Median = 3.2
<span>So this shows that B is the answer because the median of B is 3.2.
C.
1.8, 2.0, 2.0, 2.2, 3.2, 4.7, 4.8, 4.9
</span>
Even numbers = 8
2.2 + 3.2 = 5.4
5.4 ÷ 2 = 2.7
Median = 2.7
<span>So this shows that C isn't the answer because the median of C is 2.7, not 3.2.
</span>
D.
1.4, 1.7, 2.9, 3.0, 3.1, 3.2, 3.2, 3.2, 4
Odd numbers = 9
Median = 3.1
<span>So this shows that D isn't the answer because the median of D is 3.1, not 3.2.
</span>
The stem and leaf plot which median is 3.2 is B.
Discriminant = square root (b^2 -4*a*c)
square root (64 -4*1*12) =
square root (16) =
4
Therefore it has 2 rational soltions
Steps to Solve:
29.3 = 1.7y
29.3/1.7 = 1.7y/1.7
y = 17.2352941176
In this case, we round up the hundredths place because the number in the thousandths place is 5 or higher.
y = 17.24
Hope this helps!! :)