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3 years ago

6

Factor 140c + 28 - 14a to identify the equivalent expressions.

1 answer:

Feliz [49]3 years ago

8 0

Answer:

The answer to your question are letters A, C and D.

Step-by-step explanation:

To factor this polynomial we need to look for the common factor of the three terms.

To find it, get the greatest common factor

140 28 14 2

70 14 7 2

35 7 7 5

7 7 7 7

1 1 1

Greatest common factor = 2 x 7 = 14

Factor the polynomial

140c + 28 - 14a = 14 ( 10c + 2 - a)

Factor only 7 7(20c + 4 - 2a)

Factor only 2 2 (70c + 14 - 7a)

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3 years ago

What is the median of 7, 12, 13, 40, 88, 95, 95 HURRY!!

bija089 [108]

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3 years ago

Please help me with these, oh sweet jesus

Lelechka [254]

Answer:

77. $\cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} x$ Proved

78. $\sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ]$ Proved

79. $\cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x$ Proved.

80. $\sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x$ Proved.

Step-by-step explanation:

77. Left hand side

= $\cot^{6} x$

= $\cot^{4} x \times \cot^{2} x$

= $\cot^{4}x [\csc^{2}x - 1]$

{Since we know, $\csc^{2} x - \cot^{2}x = 1$ }

= $\cot^{4} x \csc^{2}x - \cot^{4} x$

= Right hand side (Proved)

78. Left hand side

= $\sec^{4}x \tan^{2} x$

= $\sec^{2} x [1 + \tan^{2}x] \tan^{2} x$

{Since $\sec^{2}x - \tan^{2}x = 1$ }

= $\sec^{2}x [\tan^{2}x + \tan^{4}x ]$

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79. Left hand side

= $\cos^{3} x\sin^{2} x$

= $\cos x[1 - \sin^{2} x] \sin^{2} x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $[\sin^{2}x - \sin^{4}x] \cos x$

= Right hand side

80. Left hand side

= $\sin^{4}x - \cos^{4}x$

= $[\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $1 - 2\cos^{2} x[1 - \cos^{2}x ]$

= $1 - 2\cos^{2}x + 2 \cos^{4} x$

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7 0

3 years ago

Solve the equation <br> 14(3x-1)=2x-23

irina1246 [14]

Answer:

$x=\frac{-9}{40} \\$

Step-by-step explanation:

Given Equation:

$14(3x-1)=2x-23$

Solving the bracket on L.H.S

$(14)(3x)-1(14)=2x-23$

$42x-14=2x-23$

Taking the terms of 'x' to one side and the constants to other side

$42x-2x=-23+14\\\\40x=-9\\\\x=\frac{-9}{40} \\$

The value of 'x' after solving the equation is:

$x=\frac{-9}{40} \\$

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deff fn [24]

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Step-by-step explanation:

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3 years ago