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Bingel [31]
3 years ago
15

Quadrilateral ABCD is similiar to quadrilateral EFGH. The lengths of the three longest sides in quadrilateral ABCD are 60 feet,

40 feet, and 30 feet long. If the two shortest sides of quadrilateral EFGH are 6 feet long and 12 feet long, how long is the 4th side on quadrilateral ABCD? A) 18 feet B) 24 feet C)16 feet D)20 feet
Mathematics
1 answer:
babunello [35]3 years ago
8 0

Answer:

15 feet

Step-by-step explanation:

It is given that Quadrilateral ABCD is similar to Quadrilateral EFGH. This means that the corresponding sides of these two quadrilateral will be in the same proportion.

i.e.

Ratio of two corresponding sides would be the same. We are given longest three sides of ABCD and shortest two sides of EFGH. Let the 4th sides of ABCD i.e. the shortest side be x.

So, the ratio of the shortest sides of two quadrilaterals would be the same as the ratio of second shortest sides.

So,

x:6=30:12\\\\\frac{x}{6}=\frac{30}{12}\\\\ x=\frac{30}{12} \times 6\\\\ x = 15

So, the 4th side on quadrilateral ABCD would be 15 feet. None of the options match with the answer.

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Find the angle between the hands of a clock at 5:15<br><br> A 60<br> B 67.5<br> C 75
Viktor [21]

Answer:

Option B is correct.

67.5 degree

Step-by-step explanation:

To find the angle between the hands of a clock.

Given that:

Hands of a clock at 5 : 15.

We know that:

A clock is a circle and it always contains 360 degree.

Since, there are 60 minutes on a clock.

\frac{360^{\circ}}{60 minutes} = 6^{\circ} per minutes

so,  each minute is 6 degree.

The minutes hand on the clock will point at 15 minute,

then, its position on the clock is:

(15) \cdot 6^{\circ} = 90^{\circ}

Also, there are 12 hours on the clock

⇒Each hour is 30 degree.

Now, can calculate where the hour hand at 5:00 clock.

⇒5 \cdot 30 =150^{\circ}

Since, the hours hand is between 5 and 6 and we are looking for 5:15 then :

15 minutes is equal to \frac{1}{4} of an hour

⇒150+\frac{1}{4}(30) = 150+7.5 = 157.5^{\circ}

Then the angle between two hands of clock:

⇒\theta = 150.75 -90 = 67.5^{\circ}

Therefore, the angle between the hands of a clock at 5: 15 is: 67.5 degree.

4 0
3 years ago
Read 2 more answers
The diagonal of a TV set is 13 inches long. It’s length is 7 inches more than the height. Find the dimensions of the TV set.
alukav5142 [94]

Answer: The length is 12 inches while the height is 5 inches

Step-by-step explanation: It the Television has a diagonal of 13 inches, and a height of H inches, then the length would be (H + 7) inches. It’s length is 7 inches more than the height. At this point we can draw up a right angled triangle with the hypotenuse as 13 (diagonal side) and the other two sides as H and (H + 7)

Then we can apply the Pythagoras theorem which states that

AC^2 = AB^2 + BC^2

(Where AC is the hypotenuse and AB and BC are the two other sides)

Hence,

13^2 = H^2 + (H + 7)^2

169 = H^2 + (H^2 + 14H + 49)

169 = 2H^2 + 14H + 49

By collecting like terms we now have

169 - 49 = 2H^2 + 14H

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By re-arranging all terms on one side of the equation, we arrive at

2H^2 + 14H - 120 = 0

Divide all sides by 2

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To solve the quadratic equation, we now factorize and we have,

H^2 + 12H - 5H - 60 = 0

(H + 12) (H - 5) = 0

Therefore

Either H + 12 = 0 OR

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Hence, Either H = -12 or H = 5

The dimension can not be a negative value so we shall take h equals 5.

Having calculated the height of the television as 5 inches, the length which was given as H + 7 can now be calculated as

Length = H + 7

Length = 5 + 7

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Therefore, the length of the Television is 12 inches and the height is 5 inches

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Answer: The answer would be

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