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3 years ago

12

The distance between major cracks in a highway follows an exponential distribution with a mean of four miles. (a) what is the st

andard deviation of the distance between two major cracks

1 answer:

Lesechka [4]3 years ago

7 0

For an exponential distribution, the standard deviation is equal to the mean.

(a) the standard deviation is 4 miles.

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The probability that an egg on a production line is cracked is 0.01. Two eggs are selected at random from the production line. F

musickatia [10]

Answer:

$P(X \geq 1)=1-P(X$

$P(X=0)=(2C0)(0.01)^0 (1-0.01)^{2-0}=0.9801$

And replacing we got:

$P(X \geq 1) = 1-0.9801 = 0.0199$

Step-by-step explanation:

Let X the random variable of interest "number of craked eggs", on this case we now that:

$X \sim Binom(n=2, p=0.01)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want to find this probability:

$P(x \geq 1)=1-P(X$

And we can find the probability:

$P(X=0)=(2C0)(0.01)^0 (1-0.01)^{2-0}=0.9801$

And replacing we got:

$P(X \geq 1) = 1-0.9801 = 0.0199$

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2 years ago

Geometry, please answer question ASAP

vladimir1956 [14]

Answer:

i think 60 degree is the answer

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3 years ago

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Y=1/2x+2 which graph represents the function

Tanya [424]

Answer:

Graph number 1

Step-by-step explanation:

According to the equation the y-intercept is 2. The only graph with the y-intercept of (0,2) is the first graph. So, graph number 1 represents the function.

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3 years ago

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A cab ride f I'm your home to the airport cost $23.47. If you want to tip the cab driver close to 10 percent of the fare, how mu

Westkost [7]

10% of 23.47 is 2.347 so about $2.35

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3 years ago

The table below represents the height of a bird above the ground during flight, with p(t) representing height in feet and t repr

ddd [48]

Answer:

3.23

Step-by-step explanation:

6.26+6+3.41=15.67

15.67/7=3.23

I have mentioned time 7 sec from 3 to9

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3 years ago

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