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Tema [17]
3 years ago
5

The side was cut off The value of X is Will mark brainiest!!!!

Mathematics
1 answer:
Kay [80]3 years ago
7 0

Answer:

x=240

Step-by-step explanation:

Due to the fact that they are vertical angles each side have to equal 40 because one side is already given so.... we set the numbers equal to each other:

40=x/6

Then we multiply each side by 6 because we want to get x by its self because that is what we are looking for:

6*40=x

So then that means 6*40 is 240 therefore x=240.

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Solve the system below by substitution. Give your answer as an ordered pair.
bearhunter [10]
Work:
2x+5(6x+23)=-13
2x+30x+115=-13
32x=-128
x=-4

y=6(-4)+23
y=-24+23
y=-1

The answer is (-4,-1)

Hopefully this helps!
6 0
3 years ago
In a certain population of the eastern thwump bird, the wingspan of the individual birds follows an approximately normal distrib
Greeley [361]

Answer:

a) P(48 < x < 58) = 0.576

b) P(X ≥ 1) = 0.9863

c) E(X) 2.88

d) P(x < 48) = 0.212

e) P(X > 2) = 0.06755

Step-by-step explanation:

The mean of the wingspan of the birds = μ = 53.0 mm

The standard deviation = σ = 6.25 mm

a) Probability of a bird having a wingspan between 48 mm and 58 mm can be found by modelling the problem as a normal distribution problem.

To solve this, we first normalize/standardize the two wingspans concerned.

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ

For wingspan 48 mm

z = (48 - 53)/6.25 = - 0.80

For wingspan 58 mm

z = (58 - 53)/6.25 = 0.80

To determine the probability that the wingspan of the first bird chosen is between 48 and 58 mm long. P(48 < x < 58) = P(-0.80 < z < 0.80)

We'll use data from the normal probability table for these probabilities

P(48 < x < 58) = P(-0.80 < z < 0.80) = P(z < 0.8) - P(z < -0.8) = 0.788 - 0.212 = 0.576

b) The probability that at least one of the five birds has a wingspan between 48 and 58 mm = 1 - (Probability that none of the five birds has a wingspan between 48 and 58 mm)

P(X ≥ 1) = 1 - P(X=0)

Probability that none of the five birds have a wingspan between 48 and 58 mm is a binomial distribution problem.

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = number of birds = 5

x = Number of successes required = number of birds with wingspan between 48 mm and 58 mm = 0

p = probability of success = Probability of one bird having wingspan between 48 mm and 58 mm = 0.576

q = probability of failure = Probability of one bird not having wingspan between 48 mm and 58 mm = 1 - 0.576 = 0.424

P(X=0) = ⁵C₀ (0.576)⁰ (1 - 0.576)⁵ = (1) (1) (0.424)⁵ = 0.0137

The probability that at least one of the five birds has a wingspan between 48 and 58 mm = P(X≥1) = 1 - P(X=0) = 1 - 0.0137 = 0.9863

c) The expected number of birds in this sample whose wingspan is between 48 and 58 mm.

Expected value is a sum of each variable and its probability,

E(X) = mean = np = 5×0.576 = 2.88

d) The probability that the wingspan of a randomly chosen bird is less than 48 mm long

Using the normal distribution tables again

P(x < 48) = P(z < -0.8) = 1 - P(z ≥ -0.8) = 1 - P(z ≤ 0.8) = 1 - 0.788 = 0.212

e) The probability that more than two of the five birds have wingspans less than 48 mm long = P(X > 2) = P(X=3) + P(X=4) + P(X=5)

This is also a binomial distribution problem,

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = number of birds = 5

x = Number of successes required = number of birds with wingspan less than 48 mm = more than 2 i.e. 3,4 and 5.

p = probability of success = Probability of one bird having wingspan less than 48 mm = 0.212

q = probability of failure = Probability of one bird not having wingspan less than 48 mm = 1 - p = 0.788

P(X > 2) = P(X=3) + P(X=4) + P(X=5)

P(X > 2) = 0.05916433913 + 0.00795865476 + 0.00042823218

P(X > 2) = 0.06755122607 = 0.06755

5 0
2 years ago
In your new home, you are planning to completely re-landscape the backyard. the yard is 18 feet long and 20 Feet Wide. a contrac
Sedbober [7]

Answer:

$2520

Step-by-step explanation:

18 times 20 = 360

360 time 7 = 2520

7 0
2 years ago
Describe, in at least 3 sentences, the difference between when a quadratic function opens upward and downward.
fomenos
There is an easy way to tell whether the graph of a quadratic function opens upward or downward: if the leading coefficient is greater then zero, the parabola opens upward, and if the leading coefficient is less than zero, the parabola opens downward. Study the graphs below: Figure %: On the left, y= x2.
7 0
2 years ago
Find the circumstances of a circle if the area is 300 square centimeter
sergiy2304 [10]

It will be 61 rounded.

Here the link I used

https://www.piday.org/calculators/circle-calc-find-c-d-a-r/#

6 0
2 years ago
Read 2 more answers
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