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Orlov [11]
3 years ago
10

What is the difference of the polynomials?

Mathematics
2 answers:
Olenka [21]3 years ago
8 0
(5x³ + 4x²) - (6x² - 2x - 9)

-1(6x²) -1(-2x) -1(-9) = -6x² + 2x + 9

5x³ + 4x² - 6x² + 2x + 9

5x³ - 2x² + 2x + 9  Choice D.


Brilliant_brown [7]3 years ago
8 0
If you would like to solve <span>(5x^3 + 4x^2) - (6x^2 - 2x - 9), you can do this using the following steps:

</span>(5x^3 + 4x^2) - (6x^2 - 2x - 9) = <span>5x^3 + 4x^2 - 6x^2 + 2x + 9 = 5x^3 - 2x^2 + 2x + 9
</span>
The correct result would be <span>D. 5x^3 – 2x^2 + 2x + 9.</span>
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Solve. x - 6 = 3 A) x = -3 B) x = 2 C) x = 3 D) x = 9 Please Help im trying to get my grades up
kirza4 [7]

x=9

Add 6 to both sides of the equation. x = 3 + 6

Add 3and 6.

x=9

6 0
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For what values of x will 8+x to the third power be negative
Ganezh [65]

(8+x)^3 < 0

take the cube root

8+x <0

subtract 8

x<-8

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6 0
4 years ago
How do I solve 6v-5/8=7/8
astra-53 [7]
6v-5/8=7/8
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3 0
3 years ago
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Marrrta [24]

y = -2x + 1

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5 0
3 years ago
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John and Jane are married. The probability that John watches a certain television show is .7. The probability that Jane watches
ikadub [295]

a) The probability  that both John and Jane watch the show is 0.12.

b.The probability that Jane watches the show, given that John does is  0.1714.

c)They do watch show independent of each other.

Step-by-step explanation:

Here, as given in the question:

Probability that John watches a certain show  = 0.7   ⇒ P(J) = 0.7

Probability that Jane watches a certain show  = 0.3   ⇒ P(Je) = 0.3

Probability that John watches a certain show given Jane watches it to

 = 0.4   ⇒ P(J/Je) = 0.4

a. )  Here, we need to find the probability of  both Jane and John watching a show , P(J∩Je)

Now, by BAYES THEOREM:

P(J/Je)  = \frac{P(J \cap Je)}{P(Je)}

\implies  0.4  = \frac{P(J \cap Je)}{0.3} \\\implies P(J \cap Je) = 0.4 \times 0.3  = 0.12

Hence the probability  that both John and Jane watch the show is 0.12.

b.) The probability that Jane watches the show, given that John does is P(J/Je)

By BAYES Theorem:

P(Je/J)  = \frac{P(J \cap Je)}{P(J)}\\\implies P(Je/J)  = \frac{0.12}{0.7}  = 0.1714

Hence, the probability that Jane watches the show, given that John does is  0.1714.

c) As we can see P(Jane ∩ John) =  0.12

So, the probability of both of them seeing the show TOGETHER is 0.12.

Hence, they do watch show independent of each other and the probability of doing that is 1.0.12  = 0.88

7 0
3 years ago
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