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3 years ago

What are the major arcs of o0 that contain point B?

Mathematics

1 answer:

masha68 [24]3 years ago

6 0

Answer:

Option (C)

Step-by-step explanation:

By the definition of a major arc - any arc of a circle which measures more than 180° is the major arc.

In the given circle, AC and BD are the two chords.

And arcs measuring more than 180° are,

$(\widehat{BCA}, \widehat{CDB}, \widehat{ABD},\widehat{DAC},\widehat{DBC},\widehat{ACD})$

Therefore, the arcs given in Option (C) will be the major arcs of the circle O.

Option (C) will be the correct option.

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Which of the following is in order from largest to smallest?

daser333 [38]

Step-by-step explanation:

9,7,-1,-2..................

5 0

2 years ago

Read 2 more answers

suppose you are the financial manager of the International Emirates University IEU. And you are requested at the end of the year

Irina18 [472]

So what this is is
many words

assuming year 0 is 2017

so compound first thing till 2020, take out 30000
the remaining is copmpounded til 2022, take out 50000
remaining is compounded for 1 more year and that is equal to 80000

so from 2017 to 2020, that is 5 years
from 2020 to 2022 is 2 years
from 2022 to 2023 is 1 year

work backwards

A=P(r+1)^t
last one
A=80000
P=?
r=0.08
t=1 year

80000=P(1.08)^1
divide both sides by 1.08
I would leave in fraction
20000000/27=P

now that is the remaining after paying 50000, after 2 years of compounding

so
50000+(2000000/27)=P(1.08)^2
solve using math
about
106374=P

now reverse back

5 years
paid 30000

30000+106374=P(1.08)^5
solve using math
92813.526=P
round
$92813.53

put $92813.53 in the fund

8 0

3 years ago

MARK BRAINLIEST!!!

mash [69]

Answer:

r-100

Step-by-step explanation:

R-100 R-100 R-100

7 0

2 years ago

Please help!! Thank you so much!!

Olenka [21]

Answer:

AC, AB, BC

Step-by-step explanation:

3x-13+2x-20+x+15=180

6x-18=180

6x=198

x=33

<a 86

<b 46

<c48

3 0

2 years ago

Mixed numbers greater than 6 but less than 7 use an interval of 1/6 between each pair of numbers

GaryK [48]

Answer:

$[6\frac{1}{6},6\frac{1}{3},6\frac{1}{2},6\frac{2}{3},6\frac{5}{6}]$

Step-by-step explanation:

we have the compound inequality

$6 < x < 7$

where

x is a mixed number

The solution for the compound inequality are the numbers

$[6\frac{1}{6},6\frac{2}{6},6\frac{3}{6},6\frac{4}{6},6\frac{5}{6}]$

Simplify the numbers

$[6\frac{1}{6},6\frac{1}{3},6\frac{1}{2},6\frac{2}{3},6\frac{5}{6}]$

5 0

3 years ago