All categories

3 years ago

What are the major arcs of o0 that contain point B?

Mathematics

1 answer:

masha68 [24]3 years ago

6 0

Answer:

Option (C)

Step-by-step explanation:

By the definition of a major arc - any arc of a circle which measures more than 180° is the major arc.

In the given circle, AC and BD are the two chords.

And arcs measuring more than 180° are,

$(\widehat{BCA}, \widehat{CDB}, \widehat{ABD},\widehat{DAC},\widehat{DBC},\widehat{ACD})$

Therefore, the arcs given in Option (C) will be the major arcs of the circle O.

Option (C) will be the correct option.

You might be interested in

A local gym has 2 types of cardio machines, treadmills and elliptical machines. There are 38 cardio machines in all. There are 1

Brilliant_brown [7]

Answer:

14 elliptical machines

Step-by-step explanation:

t = # of treadmills

e = # of elliptical machines

t + e = 38

t = e + 10

Substitute:

e + 10 + e = 38

2e = 28

e = 14

6 0

3 years ago

Pls u people should help me put in this maths fast solve

mamaluj [8]

Well, you have to ask the question first.

6 0

3 years ago

The rectangle below has an area of x^2-15x+56x square meters and a length of x-7 meters.

Gennadij [26K]

$Heya \: \: ! \\ \\ \\ Area \: of \: rectangle \: = Length \: \times Width \\ \\ We \: are \: given \: that \: , \\ \\ Length \: = \: \: ( \: x - 7 \: ) \: metres \\ Area \: \: \: \: \: = \: \: \: ( \: {x}^{2} - 15x + 56 \: ) \: square \: meters \\ \\ Therefore \: \: , \: \\ {x}^{2} - 15x + 56 = ( \: x - 7) \times Width \\ \\ Width = \frac{ ({x}^{2} - 15x + 56 )}{(x - 7)} \\ \\ Width = \frac{(x - 7)(x - 8)}{(x - 7)} \\ \\ \\ Width = ( \: x - 8 \: ) \: \: m \: \: \: \: \: \: \: \: \: Ans.$

3 0

3 years ago

48 notebooks to 14 notebooks

rewona [7]

Set up a x/100 = (14-48)/48 = -34/48 Multiply the cross 48x = -3400 x = 70.8333 so around -70.83% change

3 0

3 years ago

Points 2

jonny [76]

Answer:

a = -1,6 b = 1,11 c = 4,11 .

4 0

3 years ago