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dusya [7]
3 years ago
14

If every action has an equal and opposite reaction, then when you jump, and gravity pulls you back down, it also pulls the Earth

up to you. Why can’t you see this motion?
Physics
1 answer:
LenKa [72]3 years ago
8 0

When two objects are gravitationally attracted, the forces

on both of them are equal. As the objects move straight

toward each other, then, just as we'd expect, the object

with the greater mass has the smaller acceleration and

moves a smaller distance by the time they collide, while

the object with a smaller mass has the greater acceleration

and moves a greater distance by the time they collide.


The Earth's mass is roughly approximately something like 70,000,000,000,000,000,000,000 times as much as YOUR mass,

so the difference in acceleration and distance moved before

the collision is really substantial.

You might be interested in
Please Help ASAP!!!
const2013 [10]

Answer:

The Forces of Flight

At any given time, there are four forces acting upon an aircraft.  

These forces are lift, weight (or gravity), drag and thrust. Lift is  

the key aerodynamic force that keeps objects in the air. It is the  

force that opposes weight; thus, lift helps to keep an aircraft in  

the air. Weight is the force that works vertically by pulling all  

objects, including aircraft, toward the center of the Earth. In order  

to fly an aircraft, something (lift) needs to press it in the opposite  

direction of gravity. The weight of an object controls how strong  

the pressure (lift) will need to be. Lift is that pressure. Drag is a  

mechanical force generated by the interaction and contract of a  

solid body, such as an airplane, with a fluid (liquid or gas). Finally,  

the thrust is the force that is generated by the engines of an  

aircraft in order for the aircraft to move forward.

Explanation:

5 0
2 years ago
The process by which people walk A) requires only a little energy. B) is powered by the body’s surplus heat energy. C) relies on
Andreyy89
I think the answer would be c
4 0
3 years ago
Read 2 more answers
At the local swimming hole, a favorite trick is to run horizontally off a cliff that is 8.0 m above the water. One diver runs of
Alika [10]

Answer:

Number of revolutions=1.532 revolutions

Explanation:

Given data

Distance s=8.0 m

Angular speed a=1.2 rev/s

To find

Number of revolutions

Solution

From the equation of simple motion we not that

S=ut+1/2gt^{2}\\ where\\u=0\\So\\8.0m=0+(1/2)(9.8m/s^{2} )t^{2}\\ t^{2}=\frac{8.0m}{0.5*9.8m/s^{2} } \\ t^{2}=1.63\\t=\sqrt{1.63} \\t=1.28s

So for the number of revolutions she makes is given as

n=a*t\\n=(1.2rev/s)(1.28s)\\n=1.532revolutions

8 0
3 years ago
Find the shear stress and the thickness of the boundary layer (a) at the center and (b) at the trailing edge of a smooth flat pl
melomori [17]

Answer:

a) The shear stress is 0.012

b) The shear stress is 0.0082

c) The total friction drag is 0.329 lbf

Explanation:

Given by the problem:

Length y plate = 2 ft

Width y plate = 10 ft

p = density = 1.938 slug/ft³

v = kinematic viscosity = 1.217x10⁻⁵ft²/s

Absolute viscosity = 2.359x10⁻⁵lbfs/ft²

a) The Reynold number is equal to:

Re=\frac{1*3}{1.217x10^{-5} } =246507, laminar

The boundary layer thickness is equal to:

\delta=\frac{4.91*1}{Re^{0.5} }  =\frac{4.91*1}{246507^{0.5} } =0.0098 ft

The shear stress is equal to:

\tau=0.332(\frac{2.359x10^{-5}*3 }{1}  )(246507)^{0.5} =0.012

b) If the railing edge is 2 ft, the Reynold number is:

Re=\frac{2*3}{1.215x10^{-5} } =493015.6,laminar

The boundary layer is equal to:

\delta=\frac{4.91*2}{493015.6^{0.5} } =0.000019ft

The sear stress is equal to:

\tau=0.332(\frac{2.359x10^{-5}*3 }{2}  )(493015.6^{0.5} )=0.0082

c) The drag coefficient is equal to:

C=\frac{1.328}{\sqrt{Re} } =\frac{1.328}{\sqrt{493015.6} } ==0.0019

The friction drag is equal to:

F=Cp\frac{v^{2} }{2} wL=0.0019*1.938*(\frac{3^{2} }{2} )(10*2)=0.329lbf

7 0
3 years ago
A guitar string vibrates at a frequency of 330Hz with wavelength 1.40m. The frequency and wavelength of this sound wave in air (
bixtya [17]

Answer:

Same frequency, shorter wavelength

Explanation:

The speed of a wave is given by

v=f\lambda

\lambda=\dfrac{v}{f}

where,

f = Frequency

\lambda = Wavelength

It can be seen that the wavelength is directly proportional to the velocity.

Here the frequency of the sound does not change.

But the velocity of the sound in air is slower.

Hence, the frequency remains same and the wavelength shortens.

7 0
3 years ago
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