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2 years ago

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Physics

1 answer:

const2013 [10]2 years ago

5 0

Answer:

The Forces of Flight

At any given time, there are four forces acting upon an aircraft.

These forces are lift, weight (or gravity), drag and thrust. Lift is

the key aerodynamic force that keeps objects in the air. It is the

force that opposes weight; thus, lift helps to keep an aircraft in

the air. Weight is the force that works vertically by pulling all

objects, including aircraft, toward the center of the Earth. In order

to fly an aircraft, something (lift) needs to press it in the opposite

direction of gravity. The weight of an object controls how strong

the pressure (lift) will need to be. Lift is that pressure. Drag is a

mechanical force generated by the interaction and contract of a

solid body, such as an airplane, with a fluid (liquid or gas). Finally,

the thrust is the force that is generated by the engines of an

aircraft in order for the aircraft to move forward.

Explanation:

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Nezavi [6.7K]

Answer:

The liquid turns to a gas.

Explanation:

If a liquid is heated the particles are given more energy and move faster and faster expanding the liquid. Particles in the middle of the liquid form bubbles of gas in the liquid.

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2 years ago

An athlete is running a 400m race around a 400m track. On the backstretch the athlete's velocity is 8m/s but he is running into

Aleksandr-060686 [28]

Answer:

33 N

Explanation:

v = Velocity of fluid = 8+2 = 10 m/s

$\rho$ = Density of fluid = 1.2 kg/m³

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A = Cross sectional area = 0.5 m²

Drag force is given by

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The drag force on the athlete is 33 N

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2 years ago

Chapter 36, Problem 007 Light of wavelength 586 nm is incident on a narrow slit. The angle between the first diffraction minimum

svp [43]

Answer:

$d =4.77\times 10^{-5}\ m$

Explanation:

given

wavelength of light λ = 479 nm

= 479 x 10⁻⁹ m

the angle

θ = 1.15 / 2 = 0.575°

using

condition for diffraction minimum ,

d sinθ = m λ

for first minimum m = 1

d sinθ = λ

therefore ,

slit width

$d =\dfrac{\lambda}{sin\theta}$

$d =\dfrac{479\times 10^{-9}}{sin 0.575^0}$

$d =\dfrac{479\times 10^{-9}}{0.01}$

$d =4.77\times 10^{-5}\ m$

hence, the width of the slit is equal to $d =4.77\times 10^{-5}\ m$

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2 years ago

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Answer:

Mass released = 8.6 g

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Final mass of nitrogen released = ?

Final volume = 17.3 L

Formula:

V₁/n₁ = V₂/n₂

25.5 L / 0.950 mol = 17.3 L/n₂

n₂ = 17.3 L× 0.950 mol/25.5 L

n₂ = 16.435 L.mol /25.5 L

n₂ = 0.644 mol

Initial mass of nitrogen:

Mass = number of moles × molar mass

Mass = 0.950 mol × 28 g/mol

Mass = 26.6 g

Final mass of nitrogen:

Mass = number of moles × molar mass

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3 years ago

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alexdok [17]

Answer:

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Explanation:

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