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mars1129 [50]
3 years ago
10

What is the distance from the earth's center to a point outside the earth where the gravitational acceleration due to the earth

is 1/40 of its value at the earth's surface?
Physics
1 answer:
Crazy boy [7]3 years ago
8 0
R2^ 2 / R1 ^2 = g1 / g2 = 38 

<span>R2 = R1 x √38 = 6.1644* R1 </span>

<span>R2 = 6.1644 x 6378 000 = 39316632.5 m</span>
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A drop of oil of volume 10m it spread out on water to make a circular firm of radius 10m calculate the tickness of the firm
Effectus [21]

Answer:

h = 3.1 cm

Explanation:

Given that,

The volume of a oil drop, V = 10 m

Radius, r = 10 m

We need to find the thickness of the film. The film is in the form of a cylinder whose volume is as follows :

V=\pi r^2 h\\\\h=\dfrac{V}{\pi r^2}\\\\h=\dfrac{10}{\pi \times 10^2}\\\\h=0.031\ m\\\\h=3.1\ cm

So, the thickness of the film is equal to 3.1 cm.

8 0
3 years ago
How can you change the phases of matter using thermal energy
Leokris [45]

Answer:

These energy exchanges are not changes in kinetic energy. They are changes in bonding energy between the molecules. If heat is coming into a substance during a phase change, then this energy is used to break the bonds between the molecules of the substance.

8 0
3 years ago
How much potential energy does a 40-kg medicine ball gain when it is lifted 5 m? Use the formula: GPE= mass X gravity (9.8 m/s2)
Ronch [10]
The answer is c: <span>1960 J

</span>Potential Energy :
<span>PE = m x g x h = 40*9.8*5=1960
</span>
4 0
3 years ago
Mason notices that his boat sinks lower into the water in a freshwater lake than in the ocean. What could explain this?
zloy xaker [14]

Answer:

Salt water is more dense than freshwater.

8 0
3 years ago
Read 2 more answers
Parasaurolophus was a dinosaur whose distinguishing feature was a hollow crest on the head. The 1.3 m long hollow tube in the cr
yarga [219]

Answer:

67.31 Hz, 201.92 Hz, 336.54 Hz

Explanation:

Resonance also known as standing wave occur when a uniform tube is closed at one end and open at the other end.  

For a resonance wave in a tube with length b, wavelength λ of resonance wave is 4b because a quarter wave is formed in the tube, that is,  

           λ = 4b.  

When the speed of sound is c, the frequency of sound, f, is  

           f = c /λ,  

and therefore,  

           f = c / ( 4b ).  

From the question,

When c = 350 m/s and b = 1.3 m,  

using the formula            

fn = c / ( 4b ) × n (n = 1, 3, 5, ...).  

The first three resonant frequencies are;

First resonance frequency is

f = 350 / (4*1.3) * 1 = 67.31 Hz

Second resonance frequency is

f = 350 / (4*1.3) * 3 = 201.92 Hz

Third resonance frequency is

f = 350 / (4*1.3) * 5 = 336.54 Hz

5 0
3 years ago
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