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3 years ago

12

I was watching quantum leap and I was wondering if we can actually travel through different people's body without knowing it's a

ctually me.

1 answer:

alukav5142 [94]3 years ago

7 0

Answer:

No you could not do that because if you tried even if you where to go super fast they would feel a breif second of pain before being completely riped from there body

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A very long solid insulating cylinder has radius R = 0.1 m and uniform charge density rho0= 10-3 C/m3. Find the electric field a

Galina-37 [17]

Answer:

$E = (0.56 \times 10^8 ) r \ \ N/c$

Explanation:

Given that:

$\rho_o = (10^{-3} ) \ c/m^3$

R = (0.1) m

To find the electric field for r < R by using Gauss Law

${\oint}E^{\to}* da^{\to} = \dfrac{Q_{enclosed}}{\varepsilon_o} --- (1)$

For r < R

$Q_{enclosed}=(\rho) ( \pi r^2 ) l$

$E*(2 \pi rl)= \dfrac{\rho ( \pi r ^2 l)}{\varepsilon_o}$

$E= \dfrac{\rho ( r)}{2 \varepsilon_o}$

where;

$\varepsilon_o = 8.85 \times 10^{-12}$

$E= \dfrac{10^{-3} ( r)}{2 (8.85 \times 10^{-12})}$

$E= \dfrac{10^{-3} ( r)}{2 (8.85 \times 10^{-12})}$

$E = (0.56 \times 10^8 ) r \ \ N/c$

4 0

3 years ago

A Net Force of 9.0 N acts through a distance of 3.0 m in a time of 3.0 s. The work done is?

JulijaS [17]

Work done is the distance a force acts over.

So, the work done here is 9.0N * 3.0m = 27 J

5 0

3 years ago

Read 2 more answers

We want to design a cylindrical vacuum capacitor, with a given radius a for the outer cylindrical shell, that will be able to st

anastassius [24]

Solution :

a). Using Gauss's law :

$E=\frac{Q}{4 \pi \epsilon_0r^2}$ , $$b$ .........(1)

Let $E=E_0,\ r=b$ in equation (1)

Therefore, $Q=4 \pi \epsilon_0b^2E_0$ .............(2)

$V_b-V_a = \int^a_b \vec E. d\vec l$

$=\int^a_b E \ dx$

$=\frac{Q}{4 \pi \epsilon_0} \int^a_b \frac{1}{x^2} \ dx$

$=\frac{Q(a-b)}{4 \pi \epsilon_0 a b}$ ....................(3)

Therefore, $U=\frac{1}{2}Q \Delta V$

$=\frac{1}{2}(4 \pi \epsilon_0 b^2 E_0)\left(\frac{Q(a-b)}{4\pi \epsilon_0 a b}\right)$

$=\frac{4 \pi \epsilon_0}{2a} \ E^2_0 b^3(a-b)$ .............(4)

Now differentiating the equation (4) w.r.t. 'b', we get

$b=\frac{3}{4}a$

Thus the radius for the inner cylinder conductor is $b=\frac{3}{4}a$

b). For the energy storage, substitute the radius in (4), we get

$U = 4 \pi\epsilon_0 \frac{27a^3E^2_0}{512}$

This is the amount of energy stored in the conductor.

8 0

3 years ago

The host says during the video that her interests during middle school were?

Jobisdone [24]

Answer:

huh? What video?

Explanation:

7 0

3 years ago

What has been gravity's apparent role in our solar system so far? Focus on the formation of planets, individual orbits, alignmen

masya89 [10]

Gravity is one of the significant forces of the universe. It is the force that draws other objects closer to the center of another object. The bigger the object, the higher its force of gravity and nearby objects are accelerated towards the big mass.

It is this force of gravity that keeps the planets in the solar system orbiting around the sun. The suns gravitational pull is stronger than those of the planets hence pulls the planets on their orbits around the star. Gravity also played a part in the formation of the planets. Gravity caused the condensation of dust and rocks into a mass that continually attracted more matter as it gained mass (due to gaining more associated gravitational pull).

6 0

3 years ago