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Andrej [43]
4 years ago
12

Right 45.803 in expanded form can you tell me the answer stuk

Mathematics
1 answer:
aleksley [76]4 years ago
8 0

45.803 = 40 + 5 + 0.8 + 0.003 need any explanations just ask

hope this helps!

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The amount of time that a 4th grader reads comic books in a week is normally distributed with a mean of 6 hours and a standard d
KATRIN_1 [288]

Answer:

0.9544 = 95.44% probability that the sample mean time for reading comic books per week is between 5 and 7 hours.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 6, \sigma = 2, n = 16, s = \frac{2}{\sqrt{16}} = 0.5

What is the probability that the sample mean time for reading comic books per week is between 5 and 7 hours

This is the pvalue of Z when X = 7 subtracted by the pvalue of Z when X = 5. So

X = 7

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{7 - 6}{0.5}

Z = 2

Z = 2 has a pvalue of 0.9772

X = 5

Z = \frac{X - \mu}{s}

Z = \frac{5 - 6}{0.5}

Z = -2

Z = -2 has a pvalue of 0.0228

0.9772 - 0.0228 = 0.9544

0.9544 = 95.44% probability that the sample mean time for reading comic books per week is between 5 and 7 hours.

6 0
3 years ago
What is the volume of a sphere when the diameter is 10​
Mashutka [201]

if the diameter is 10, its radius is half that, or 5.

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=5 \end{cases}\implies V=\cfrac{4\pi (5)^3}{3}\implies V=\cfrac{500\pi }{3} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill V\approx 523.599~\hfill

8 0
3 years ago
Read 2 more answers
I NEED HELP ASAP!! PLEASE HELP!!!
Nimfa-mama [501]

x+15 less or equal to 60: x is the extra you can spend

3 0
4 years ago
Read 2 more answers
An athletics squad trains on a long straight track with dots marked at 10m intervals. The coach sets out cones on some of the do
Sedaia [141]

Answer:

There are 6 ways to run 10 m between two cones of the four cones giving a maximum available distance to run as 60 meters

Step-by-step explanation:

The parameters given are

Distance between two cones = 10 m

Number of cones = 4

Therefore, number of ways to choose two 10 m distances (distance between two cones) from the four cones = \binom{4}{2} = 6

Hence there are only six 10 m distances to run between two cones which gives a maximum distance available to run as 60 m.

8 0
3 years ago
Homework problem #7: 24567389+35432611=what there is soo much regrouping, could someone show me how to do it?
Natasha_Volkova [10]

Answer:

24567389+35432611 =60000000

Step-by-step explanation:

Given

24567389+35432611 =

Required

Solve

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

<em>The numbers in parentheses are carried from previous sum</em>

Start from the right

9 + 1 = 10 \to Write 0, carry 1

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

                         0

8 + 1 + (1) = 10 \to Write 0 carry 1

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

                       0 0

6 +3 + (1) = 10 \to Write 0 carry 1

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

                   0 0 0

7+2 + (1) = 10 \to Write 0 carry 1

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

                0 0 0 0

6 +3 + (1) = 10 \to Write 0 carry 1

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

             0  0 0 0 0

5 +4 + (1) = 10 \to Write 0 carry 1

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

         0  0  0 0 0 0

4 +5 + (1) = 10 \to Write 0 carry 1

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

      0  0  0  0 0 0 0

2 +3 + (1) = 6 \to Write 6

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

 6  0  0  0  0 0 0 0

Hence:

24567389+35432611 =6  0  0  0  0 0 0 0

8 0
3 years ago
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