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Yakvenalex [24]
3 years ago
15

Steven purchases a bowl. The diameter of the bowl is 14 cm. What is the circumference of the bowl?

Mathematics
1 answer:
9966 [12]3 years ago
7 0
The C of the bowl is 43.98 because C can be calculated like,  C=pi×d
And pi is about 3.14, and 3.14×14 is about 43.98
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Bo and Brica are yoga instructors. Between the both of them, they teach 46 yoga classes each week. If Brica teaches 11 fewer tha
PtichkaEL [24]

Bo teaches 19 classes and Brica teaches 27 classes per week

Step-by-step explanation:

Bo and Brica are yoga instructors

  • They teach 46 yoga classes each week
  • Brica teaches 11 fewer than twice as many as Bo

We need to find how many classes each instructor teaches per week

Assume that Bo teaches x classes per week

∵ Bo teaches x classes per week

∵ Brica teaches 11 fewer than twice as many as Bo

∵ Twice means times 2 and 11 fewer is - 11

- Multiply x by 2 and subtract 11 from the product

∴ Brica teaches 2x - 11 classes per week

∵ They teach 46 classes per week

- Add the number of their classes and equate the sum by 46

∴ x + 2x - 11 = 46

- Add the like terms in the left hand side

∴ 3x - 11 = 46

- Add 11 to both sides

∴ 3x = 57

- Divide both sides by 3

∴ x = 19

∵ Bo teaches x classes per week

∴ Bo teaches 19 classes per week

∵ Brica teaches 2x - 11 classes per week

∴ Brica teaches 2(19) - 11 = 27 classes per week

Bo teaches 19 classes and Brica teaches 27 classes per week

Learn more:

You can learn more about the linear equations in brainly.com/question/11306893

#LearnwithBrainly

5 0
3 years ago
ANSWER PLZ QUICK AND FAST
Sergio [31]

Jack had b boxes. Then he got 4 more. That is equal to:

b+4

On Wednesday, half the boxes were destroyed. To find half the amount, you can divide by 2, which is equal to:

\frac{b+4}{2}

Choice C matches the answer. Your answer is C

5 0
3 years ago
Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?
Bogdan [553]

Step-by-step explanation:

\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}

\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}

\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}

\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}

Taking sin²θ common in both numerator & denominator, We get :

\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{cot\theta = \dfrac{cos\theta}{sin\theta}}}}

\mathsf{\implies \dfrac{1 -cot^2\theta}{1 + cot^2\theta}}

\mathsf{Given :\;cot\theta = \dfrac{1}{\sqrt{5}}}

\mathsf{\implies \dfrac{1 - \left(\dfrac{1}{\sqrt{5}}\right)^2}{1 + \left(\dfrac{1}{\sqrt{5}}\right)^2}}

\mathsf{\implies \dfrac{1 - \dfrac{1}{5}}{1 + \dfrac{1}{5}}}

\mathsf{\implies \dfrac{\dfrac{5 - 1}{5}}{\dfrac{5 + 1}{5}}}

\mathsf{\implies \dfrac{5 - 1}{5 + 1}}

\mathsf{\implies \dfrac{4}{6}}

\mathsf{\implies \dfrac{2}{3}}

<u>Hence</u><u>,</u><u> option</u><u> </u><u>(</u><u>a)</u><u> </u><u>2</u><u>/</u><u>3</u><u> </u><u>is </u><u>your</u><u> </u><u>correct</u><u> </u><u>answer</u><u>.</u>

3 0
3 years ago
What is 1873 divided by 0.93
Firlakuza [10]

Answer:

it is 2013.97849462

Step-by-step explanation: hope this helps :)

6 0
3 years ago
WILL MARK BRAINLIEST! Shelly served the volleyball over the net 17 out of 25 times. What is her percentage of serving the ball o
Tju [1.3M]

Answer

68℅

Explanation

17/25 =

17 ÷ 25 =

0.68 =

0.68 × 100/100 =

0.68 × 100% =

(0.68 × 100)% =

68%;

Hope that this helps you and have a great day :)

8 0
3 years ago
Read 2 more answers
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