1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vanyuwa [196]
3 years ago
10

I don't get this question i need some help please!!!

Mathematics
2 answers:
lorasvet [3.4K]3 years ago
7 0

Answer:

2 sqrt(2) = x

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opp / hyp

sin 45 = x/4

4 sin 45 = x

4 ( sqrt(2)/2) =x

2 sqrt(2) = x

svetoff [14.1K]3 years ago
7 0

Answer: D

Use sine to find the x-value:

sin(45)=\frac{x}{4} \\\\4*sin(45)=x\\\\x=\frac{\sqrt{2} }{2} *4=2\sqrt{2}  

You might be interested in
What is the remainder when 9,857 is divided by 82? A) 16 B) 17 C) 19 D) 21
nignag [31]

Answer:

B) 17

Step-by-step explanation:

9857/82=120.....

120*82=8940

9857-9840=17

6 0
3 years ago
Read 2 more answers
Solve the equation. Round to the nearest hundredth. Show work.
muminat

Answer:

Final answer is approx x=0.16.

Step-by-step explanation:

Given equation is 2.8\times 13^{4x} +4.8 = 19.3

Now we need to solve equation 2.8\times 13^{4x} +4.8 = 19.3 and round to the nearest hundredth.

2.8\times 13^{4x} +4.8 = 19.3

2.8\times 13^{4x} = 19.3-4.8

2.8\times 13^{4x} = 14.5

13^{4x} = \frac{14.5}{2.8}

13^{4x} = 5.17857142857

\log(13^{4x}) = \log(5.17857142857)

4x \log(13) = \log(5.17857142857)

4x = \frac{\log(5.17857142857)}{\log\left(13\right)}

4x = 0.641154659628

x = \frac{0.641154659628}{4}

x = 0.160288664907

Round to the nearest hundredth.

Hence final answer is approx x=0.16.

4 0
3 years ago
Can you help me plz
Gelneren [198K]

i think the answer would be C

4 0
3 years ago
Mixed in a drawer are 44 blue​ socks, 88 white​ socks, and 44 gray socks. You pull out two​ socks, one at a​ time, without looki
MrRissso [65]

Answer:

The probability of getting 2 socks of the same color is 1/3.

Step-by-step explanation:

In the drawer,

Number of blue socks = 4

Number of white socks = 8

Number of gray socks = 4

Total number of socks  = 4 + 8 + 4 = 16

Total ways to select 2 socks form 16 socks is

^{16}C_2=\dfrac{16!}{2!(16-2)!}=120

Total ways to select 2 socks of the same color is

T = Possible ways of (2 blue + 2 white +2 gray) socks

  = ^{4}C_2+^{8}C_2+^{4}C_2

  = 6+28+6

  = 40

The probability of getting 2 socks of the same color is

Probability=\dfrac{\text{Total ways to select 2 socks of the same color}}{\text{Total ways to select 2 socks form 16 socks}}

Probability=\dfrac{40}{120}

Probability=\dfrac{1}{3}

Therefore, the probability of getting 2 socks of the same color is 1/3.

3 0
2 years ago
Since there are 6.6 laps in a mile, how many laps will you have to make to run 5 miles?
mezya [45]

Answer:

33 laps

Step-by-step explanation:

we know that

There are 6.6 laps in a mile

so

using proportion

Find how many laps will you have to make to run 5 miles

so

Let

x ----> the number of laps

\frac{6.6}{1}\frac{laps}{mile}=\frac{x}{5}\frac{laps}{mile} \\ \\x=6.6*5\\ \\ x=33\ laps

4 0
2 years ago
Other questions:
  • For a class of 25 students, 5 pizzas are needed for
    15·1 answer
  • What is 0.0625 as a square root
    14·1 answer
  • Which of the following shows two points on the line f(x)=x-7
    7·1 answer
  • the sum of the reciprocals of two consecutive even integers is 9/40. this can be represented by the equation shown 1/x + 1/(x+2)
    7·1 answer
  • How many groups of 1/2 pound are in 3 3/4 pounds?
    6·1 answer
  • .5x + 2y<br> coefficients
    12·2 answers
  • A hybrid car can travel 40 miles per gallon. Approximately how many gallons of fuel will the car need to travel 20 km? (5 points
    14·1 answer
  • Help Me !!! ASAP!!!!
    13·1 answer
  • Please answer will give brainlisit
    6·2 answers
  • What is the definition of a rational function?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!