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Vanyuwa [196]
3 years ago
10

I don't get this question i need some help please!!!

Mathematics
2 answers:
lorasvet [3.4K]3 years ago
7 0

Answer:

2 sqrt(2) = x

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opp / hyp

sin 45 = x/4

4 sin 45 = x

4 ( sqrt(2)/2) =x

2 sqrt(2) = x

svetoff [14.1K]3 years ago
7 0

Answer: D

Use sine to find the x-value:

sin(45)=\frac{x}{4} \\\\4*sin(45)=x\\\\x=\frac{\sqrt{2} }{2} *4=2\sqrt{2}  

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What is the solution to the proportion?<br> 5/x = 2/16
mixas84 [53]

Answer:

I believe the answer is X=40

Step-by-step explanation:

cross multiply 5*16 = X * 2

Multiply 5*16

80= X*2

Add '-2x' to each side of the equation

80 + -2x = 2x + -2x

Combine like terms

80 + -2x = 0

Add '-80' to each side of the equation.

80 + -80 + -2x = 0 + -80

Combine like terms: 80 + -80 = 0

0 + -2x = 0 + -80

-2x = 0 + -80

Combine like terms: 0 + -80 = -80

-2x = -80

Divide each side by '-2'.

x = 40

Simplifying

x = 40

Hope this helped :)

5 0
3 years ago
Simplify expression X^2+x-2/x^3-x^2+2x-2
professor190 [17]

Answer:


=\frac {x+2}{x^2+2} is the simplest form of given expression.


Step-by-step explanation:

The given question is \frac{x^2+x-2}{x^3-x^2+2x-2}


To solve the problem we have to group or split middle term and then factorise


\frac{x^2+(2x-x)-2}{(x^3-x^2)+(2x-2)}


Taking x^2 common from first two terms of denominator and 2 from next two terms


= \frac{x^2+2x-x-2}{x^2(x-1)+2(x-1)}


Now,taking x common from first two terms of numerator and -1 from next two terms and in denominator taking(x-1) common from both terms


= \frac{ x(x+2)-1(x+2)}{(x-1)(x^2+2)}



=\frac{(x+2)(x-1)}{(x-1)(x^2+2)}


Now cancel out x-1 from both numerator and denominator we get


=\frac {x+2}{x^2+2} is the required simplest form.



7 0
2 years ago
Find the markup and the selling price of the following item. Round answers to the nearest cent. A chemistry set costing $27.50,
postnew [5]

Let x be marked up price. We have been given that a chemistry set costing $27.50, marked up 32% on cost.

x=27.50\times\frac{32}{100}

x=27.50\times.32

x=8.8

Therefore, mark up price is $8.80.  

Since we know that selling price of any item equals the sum of cost and mark-up price of the item.

Let us find selling price of our chemistry set.  

\text{Selling price of chemistry set}=27.50+8.8

\text{Selling price of chemistry set}=36.30      

Therefore, the selling price of the chemistry set is $ 36.30.

5 0
3 years ago
Read 2 more answers
It is estimated % of all adults in United States invest in stocks and that % of U.S. adults have investments in fixed income ins
katovenus [111]

Complete question :

It is estimated 28% of all adults in United States invest in stocks and that 85% of U.S. adults have investments in fixed income instruments (savings accounts, bonds, etc.). It is also estimated that 26% of U.S. adults have investments in both stocks and fixed income instruments. (a) What is the probability that a randomly chosen stock investor also invests in fixed income instruments? Round your answer to decimal places. (b) What is the probability that a randomly chosen U.S. adult invests in stocks, given that s/he invests in fixed income instruments?

Answer:

0.929 ; 0.306

Step-by-step explanation:

Using the information:

P(stock) = P(s) = 28% = 0.28

P(fixed income) = P(f) = 0.85

P(stock and fixed income) = p(SnF) = 26%

a) What is the probability that a randomly chosen stock investor also invests in fixed income instruments? Round your answer to decimal places.

P(F|S) = p(FnS) / p(s)

= 0.26 / 0.28

= 0.9285

= 0.929

(b) What is the probability that a randomly chosen U.S. adult invests in stocks, given that s/he invests in fixed income instruments?

P(s|f) = p(SnF) / p(f)

P(S|F) = 0.26 / 0.85 = 0.3058823

P(S¦F) = 0.306 (to 3 decimal places)

3 0
3 years ago
Three roots of the polynomial equation x4 - 4x3 - 2x2 + 12x + 9 = 0 are 3, -1 and -1. Explain why the fourth root must be a real
LiRa [457]
Descares Theorem says that the number of roots of a polynomial is equal to its highest exponent, and the roots could be real and/or imaginary (complex).

However is their is one complex root (a + i.b), it's conjugate is also
a root (a-i.b).

In the equation x⁴ - 4x³ - 2x² + 12x + 9 = 0, we have already 3 roots, then the 4rth cannot be a complex one since we don't have a fifth for its conjugate.

3 0
3 years ago
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