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AnnyKZ [126]
2 years ago
11

What’s the product (6r-1)(-8r-3)

Mathematics
2 answers:
Minchanka [31]2 years ago
7 0

Answer: A

Step-by-step explanation:

Elena-2011 [213]2 years ago
4 0

\text{Use FOIL method}\ (a+b)(c+d)=ac+ad+bc+bd.\\\\(6r-1)(-8r-3)=(6r)(-8r)+(6r)(-3)+(-1)(-8r)+(-1)(-3)\\\\=-48r^2-18r+8r+3=\boxed{-48r^2-10r+3}

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Can a triangle be formed with side lengths 15, 7, and 6? Explain.
Blizzard [7]

Answer:

<h3>No.</h3>

Step-by-step explanation:

The sides would be unbalanced. To get the sides of a triangle, you have to add up the first two sides. The two sides combined usually have to be less than or equal to 15 to be considered "balanced". 22 is greater than 15, so that would leave you with an unbalanced triangle, sometimes considered degenerate. A degenerate triangle is a flat triangle that almost looks like a line. The triangle's vertices all lie on the same line, which makes it look very flat. That's why degenerate triangles are rarely considered "balanced" in regards to unit measures. So, given this is an unbalanced triangle, the answer to your question would be no.

Hope this helps!

6 0
1 year ago
Please help me.. I need the answer quick..
user100 [1]
What answer do you need it for
3 0
2 years ago
What is the relationship between the 6s in the number 7,664
vazorg [7]
It is in the ones and tens digit i think thats the answer
8 0
3 years ago
Read 2 more answers
Y= (x - 2)²-7 how do I graphic this<br>​
WITCHER [35]
Hmmm it would be kind of hard to graph as it will be a curved line but the middle of the line would be at (2,-7). Not (-2,-7).

And it will be curving upwards, meaning it will start by going down and end by going up.

Hope this helps some.
7 0
2 years ago
Suppose a poker hand contains seven cards rather than five. Compute the probabilities of the following poker hands: (a) a seven-
geniusboy [140]

Answer:

a) 0.00031

b)  0.0017

c)  0.31

d) 0.00018

Step-by-step explanation:

attached below is the detailed solution

Total number of 7-poker cards are 52P7 = 133784560

A) Determine the probabilities of Seven-card straight

probability of seven-card straight = 0.00031

B) Determine the probability of four cards of one rank and three of a different rank

P( four cards of one rank and three of different rank ) = 0.0017

C) Determine probability of three cards of one rank and two cards of each two different ranks

P( three cards one rank and two cards of two different ranks ) = 0.31

D) Determine probability of two cards of each of three different ranks and a card of a fourth rank

P ( two cards of each of three different ranks and a card of fourth rank ) =  0.00018

8 0
2 years ago
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