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3 years ago

Alexa used her compass to evenly divide the circumference of the circle below.

Mathematics

1 answer:

jok3333 [9.3K]3 years ago

3 0

Answer:

triangle
square
hexagon
dodecagon

Step-by-step explanation:

The 12 points marked can be divided into this many equal-size groups:

3, 4, 6, 12

so the figures that can be constructed are ...

triangle . . . . connects every 4th mark
square . . . . . connects every 3rd mark
hexagon . . . .connects every other mark
dodecagon . . connects every mark

_____

12 is also divisible by 1 and 2, but the minimum number of vertices in a regular polygon is 3.

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Para iniciar un negocio, una pareja pide $5.500.000 para comprar equipo y suministros. Si el préstamo tiene una tasa de 14% de i

Sunny_sXe [5.5K]

Answer:

They will have to pay $5,692,500 in 90 days.

Deben pagar $5,692,500 pagar al final de un período de 90 días.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

$E = P*I*t$

In which E are the earnings, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time, in years..

After t years, the total amount of money is:

$T = E + P$ .

In this question:

$P = 5500000, I = 0.14$

3 months is 3/12 = 1/4 = 0.25 of an year. So $t = 0.25$

Then the interest accrued is:

$E = P*I*t = 5500000*0.14*0.25 = 192500$

What they will have to pay:

$T = 192500 + 5500000 = 5692500$

They will have to pay $5,692,500 in 90 days.

Deben pagar $5,692,500 pagar al final de un período de 90 días.

7 0

3 years ago

The length of a rectangular garden is 6 more than its width. If the perimeter is 32 feet, what is the width and the area of the

PolarNik [594]

Answer:

${\fbox{ \sf{Width \: of \: a \: rectangular \: garden \: = 5 \: feet}}}$

$\boxed{ \sf{ \: Area \: of \: a \: rectangular \: garden = 55 {ft}^{2}}}$

Step-by-step explanation:

$\star$ Let the width of a rectangular garden be 'w'

$\star$ Length of a rectangular garden = 6 + w

$\star$ Perimeter of a rectangular garden = 32 feet

 $\longrightarrow$ Finding the width of a rectangular garden :

$\boxed{ \sf{ \: Perimeter \: of \: a \: rectangle \: = \: 2(length + width}}$

$\mapsto{ \text{32 = 2(6 + w + w)}}$

$\text{Step \: 1 \: : Collect \: like \: terms}$

Like terms are those which have the same base

$\mapsto{ \text{32 = 2(6 + 2w) }}$

$\text{Step \: 2 \: : Distribute \: 2 \: through \: the \: parentheses}$

$\mapsto{ \text{32 = 12 + 4w}}$

$\text{Step \: 3 \: : Swap \: the \: sides \: of \: the \: equation}$

$\mapsto{ \text{4w + 12 = 32}}$

$\text{Step \: 4 \: : Move \: 12 \: to \: right \: hand \: side \: and \: change \: its \: sign}$

$\mapsto{ \text{4w = 32 - 12}}$

$\text{Step \: 5 \: : Subtract \: 12 \: from \: 32}$

$\mapsto{ \sf{4w = 20}}$

$\text{Step \: 6 \: : Divide \: both \: sides \: by \: 4}$

$\mapsto{ \sf{ \frac{4w}{4} = \frac{20}{4}}}$

$\text{Step \: 7 \: : Calculate}$

$\mapsto{ \text{w = 5}}$

Width of a rectangular garden = 5 feet

$\longrightarrow$ Substituting / Replacing the value of w in 6 + w in order to find the length of a rectangular garden

$\mapsto{ \sf{Length = 6 + w = 6 + 5 = \bold{11 \: feet} }}$

$\longrightarrow$ Finding the area of a rectangular garden having length of 11 feet and width of 5 feet :

$\boxed{ \sf{Area \: of \: a \: rectangle = length \:∗ \: width}}$

$\mapsto{ \text{Area \: = \: 11 \: ∗ \: 5}}$

$\mapsto{ \sf{Area \: = 55 \: {ft}^{2} }}$

Area of a rectangular garden = 55 ft²

Hope I helped!

Best regards! :D

~ $\sf{TheAnimeGirl}$

6 0

3 years ago

Which pair of equations represents two perpendicular lines? Option A: -3x +2y = 10 and 3y = 2x +12 Option B: 2x + 5y = 45 and y

jek_recluse [69]

For the equation of the line expressed as Ax + By + C = 0, the value of the slope (m) is calculated by -A / B. For perpendicular lines, the slope of one should be the negative reciprocal of the other. From the choices given, the lines that are perpendicular is Option A.

8 0

3 years ago

Find the surface area of the cube (above) using its net (below).

lana66690 [7]

$\mathsf \green{ {96 \: units}^{2} }$