Answer:
Step-by-step explanation:
I have 30 coins, all nickels, dimes, and quarters, worth $4.60. There are two more dimes than quarters. How many of each kind of coin do I have.
..
let quarters be x
dimes = x+2
...
dimes + quarters = x+x+2=2x+2
...
nickels = 30-(2x+2)
...
5(30-(2x+2))+10(x+2)+25x=460
5(30-2x-2)+10x+20+25x=460
150-10x-10+10x+20+25x=460
160+25x=460
-160
25x=460-160
25x=300
/25
x=300/25
x=12 ---- quarters
x+2= 12+2=14 dimes
30-(2x+2)=4 nickels
...
check
4*5+14*10+12*25=20+140+300=460
Let c = number of children
Let a = number of adults
5a + 2c > 3350
Answer:
i think its -38
Step-by-step explanation:
Answer:
addition
Step-by-step explanation:
add 40+8 and you get 48 :P
Answer:
y=11/3
Step-by-step explanation:
just 10 plus 1 gives 11 and crisscrossing and will get 3y=11 and dividing both sides by 3 to get y free then will get y=11/3
