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Tcecarenko [31]
3 years ago
11

Tonya works 60 hours in 3 weeks. Select ALL the true statements OR YOU WILL FAIL THE GRADE.

Mathematics
2 answers:
tatuchka [14]3 years ago
6 0

Answer: b & c

Step-by-step explanation:

first i found how many hours tonya works in one week which was 20. i got that by dividing 60 by 3. then that set me up for finding the answer to the other problems as well. 60+20=80 so a wouldn’t have worked. 5x5 is 25 and she only worked 20 hours a week. and she would’ve worked 320 hours in 16 weeks, not 240. hope this helps!! :)

Jet001 [13]3 years ago
4 0

Answer:

B and C

Step-by-step explanation:

This problem is pretty simple if you know how to do some multiplication. First, we should figure out how many hours she works per week. You can figure this out by dividing 60 by 3. This gets us 20.

Now that we know how many hours she works each week, we can figure out the rest of the problems.

A is incorrect because 4 x 20 =80.

B is correct because 7 x 20 is 140.

C is correct because we did this problem earlier to solve the others.

D is in correct because 5 x 5 = 25, which does not equal 20.

E is incorrect because 16 x 20 =   320

Sorry if I'm not very good at this, as this is my first time solving someone's question.

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At time​ t, the position of a body moving along the​ s-axis is sequalsnegative t cubed plus 15 t squared minus 72 t m. a. Find t
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Answer:

Step-by-step explanation:

Given that at time t, the position of a body moving along the​ s-axis is sequalsnegative t cubed plus 15 t squared minus 72 t m

i.e. s(t) = -t^3+15t^2-72 t

Velocity is nothing but s'(t) = derivative of s

and acceleration is s"(t) = derivative of v(t)

v(t) = -3t^2+30t-72\\=-3(t^2-10t+24)\\= -3(t-6)(t-4)

a) v(t) =0 when t = 4 or 6

b) a(t) = -6t+30

a(t) =0 when t =5

c) Distance travelled by the body from 0 to 5 would be

s(5)-s(0)\\= -5^3+15(5^2)-72(5)\\= -125+375-360\\=-110

i.e. 110 miles (distance cannot be negative)

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Please solve these questions for me. i am having a difficult time understanding.
s2008m [1.1K]

Answer:

1) AD=BC(corresponding parts of congruent triangles)

2)The value of x and y are 65 ° and 77.5° respectively

Step-by-step explanation:

1)

Given : AD||BC

AC bisects BD

So, AE=EC and BE=ED

We need to prove AD = BC

In ΔAED and ΔBEC

AE=EC (Given)

\angle AED = \angel BEC ( Vertically opposite angles)

BE=ED (Given)

So, ΔAED ≅ ΔBEC (By SAS)

So, AD=BC(corresponding parts of congruent triangles)

Hence Proved

2)

Refer the attached figure

\angle ABC = 90^{\circ}

In ΔDBC

BC=DC (Given)

So,\angle CDB=\angle DBC(Opposite angles of equal sides are equal)

So,\angle CDB=\angle DBC=x

So,\angle CDB+\angle DBC+\angle BCD = 180^{\circ} (Angle sum property)

x+x+50=180

2x+50=180

2x=130

x=65

So,\angle CDB=\angle DBC=x = 65^{\circ}

Now,

\angle ABC = 90^{\circ}\\\angle ABC=\angle ABD+\angle DBC=\angle ABD+x=90

So,\angle ABD=90-x=90-65=25^{\circ}

In ΔABD

AB = BD (Given)

So,\angle BAD=\angle BDA(Opposite angles of equal sides are equal)

So,\angle BAD=\angle BDA=y

So,\angle BAD+\angle BDA+\angle ABD = 180^{\circ}(Angle Sum property)

y+y+25=180

2y=180-25

2y=155

y=77.5

So, The value of x and y are 65 ° and 77.5° respectively

8 0
4 years ago
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